point A is located at the required coordinate
You are correct about the y-intercept. In case you are unsure about the slope, you can check using y1 - y2 / x1 - x2:
(0, -1) and (1, 2)
-1 - 2 / 0 - 1
-3 / -1
3
The slope is 3; you chose the correct answer, great job.
Although I am not clear as to whether the radius is r—1 or otherwise, but if i work with the values i see then:
Volume — T. S. A.
= πr²h — (2πr²+2πrh)
So after the simplification, I substitute the values given,
r= r—1 and h=h—1
And the answer is...
π(r—1)(rh—3r—3h+5)!
Answer:
B
Step-by-step explanation:
Consider an event A happening. If we do not have enough data to estimate its actual probability, we may choose a range 0.6 to 0.9 as a first case which indicates we are quite sure it will most likely occur. If however, we have enough data, we may estimate a range of 0.7 to 0.8 as a second case that is more certain on its actual likelihood of occurrence.
Say the actual probability of the event is given as 0.75, in the first case, we can infer the probability interval as 0.75 ± 0.15 (as 0.75-0.15=0.6 and 0.75+0.15=0.9 for the lower and upper bounds respectively). In the second case, we can infer the probability interval as 0.75±0.05 (as 0.75-0.05=0.7 and 0.75+0.05=0.8 for the lower and upper bounds respectively).
Thus, we can see that with more certainty of the event happening (with more data in this case), the probability or prediction intervals are lower.
Hence, in the experiment, we will observe a narrower prediction interval for researcher A who has more (twice as many points) data than researcher B who has fewer points.
It would be 28, because it's between 18 and 36 and it's a factor of 7.
