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2 years ago

MARKING BRANLIEST HELP PLSSS!!!! d

Mathematics

1 answer:

Alenkinab [10]2 years ago

7 0

Answer:

25 inches^2

Step-by-step explanation:

The formula for the area of a triangle is A = (1/2)(base)(height).

Here the base, b, is 10 inches and the height, h, is 5 inches.

Thus, the area of this triangle is

A = (1/2)(base)(height) = (1/2)(10 inches)(5 inches) = 25 inches^2

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A 2001 study by two researchers investigated an anti-poverty initiative in Venezuela called POVERTA. POVERTA gave money to poor

ANEK [815]

Answer:

1. This is a "RANDOMIZED CONTROLLED EXPERIMENT".

A randomized controlled experiment is a type of research study, were the researcher randomly select samples in other not to be biased. This samples are separated into two groups, which are the experimental and the controlled group.

2. The research has a treatment group and a controlled group.

A treatment group are those group that received some special treatment from the researcher, it can also be called the experimental group. According to the research, the treatment group are those who are in the POVERTA scheme. That is the 320 communities.

A controlled group are those group that were not given any special treatment, but are , separated and studied. According to the research the controlled group are those 185 communities

3. This research provides evidence that being in a community receiving POVERTA benefits is associated with a lower rate of childhood illness. Because after two years, it was noticed the children in the community that receives POVERTA has low rate of illness, than the children in a community that doesn't receive the benefits of POVERTA.

4. This study does not provide evidence that being in a community receiving POVERTA benefits causes a lower rate of childhood illness. Because the research did not involve treatment of illnesses and they is no experimental evidence that shows that POVERTA benefits is interrelated with illness, as illness involves the internal functions of human body.

5. Such study will be called a "RANDOMIZED CONTROLLED EXPERIMENT". Because their randomly isolated themselves, and the POVERTA treatment was not given to them. The researcher was not based in selecting them not to participate.

3 0

2 years ago

In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate

oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = $\pi$ ×14 = 44 cm

length of arc ab = half of circumference of bigger circle = $\pi$ ×28 = $\frac{22}{7}$ ×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

= $\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}$

= $\frac{\pi }{2} (28^{2} -14^{2} )$

solving we gen area of shaded region = 924

7 0

2 years ago

I need help fast!!!

topjm [15]

Where’s the question?

8 0

2 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

2 years ago

Given right triangle MNL what is the value of cos(M)?

FromTheMoon [43]

Step $1$

Find the length of the side MN

we know that

Applying the Pythagorean Theorem

$ML^{2} =NL^{2} +MN^{2}$

Solve for MN

$MN^{2}=ML^{2} -NL^{2}$

in this problem

$ML=25\ units\\ NL=15\ units$

Substitute in the formula above

$MN^{2}=25^{2} -15^{2}$

$MN^{2}=400$

$MN=20\ units$

Step $2$

Find the value of cos (M)

we know that

in the right triangle MNL

$cos (M)=\frac{adjacent\ side\ angle\ M}{hypotenuse}$

$adjacent\ side\ angle\ M=MN=20\ units\\ hypotenuse=ML=25\ units$

Substitute

$cos (M)=\frac{20}{25}$

$cos (M)=\frac{4}{5}$

$cos (M)=0.8$

therefore

The answer is

The value of cos(M) is equal to $0.8$

6 0

3 years ago