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2 years ago

Identify the underlined place in 83.5851. Then round the number to that place. The 8 to the right is underlined.

2 answers:

8 0

We have to round the number 83.5851 to the nearest hundredth.
If the next smallest place is greater than or equal to 5 we increase the value of the digit we are rounding to by one.
83.5851 ≈ 83.59
Answer: 83.59

icang [17]2 years ago

3 0

5 - tenths
8- hundredths
5- thousanths

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A granite block in the shape of a right rectangular

Gnesinka [82]

Answer:

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3 years ago

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Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is repres

fredd [130]

Answer: D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

Step-by-step explanation:

Given : Jenny studied the characteristics of two species of bacteria. The number of bacteria of species A, A(t), after t hours is represented by the function,

$A(t) = 5 + (0.25t)^3$

The number of bacteria of species B, B(t), after t hours is represented by the function, $B(t) = 2 + 8(1.06)^t$

Then, the difference in the number of bacteria, N(t), of both the species after t hours will be :-

$N(t)=A(t)-B(t)\\\\=5 + (0.25t)^3-(2 + 8(1.06)^t)\\\\=5 + (0.25t)^3-2-8(1.06)^t\\\\=5-2 +(0.25t)^3-8(1.06)^t\\\\=3+(0.25t)^3-8(1.06)^t$

Hence, the correct answer should be : D . $N(t) = 3 + (0.25t)^3 - 8(1.06)^t$

7 0

3 years ago

Topic: The Quadratic Formula

Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

$x= \frac{-b +- \sqrt{b^2-4ac} }{2a}$

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² = x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

$x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\= -4 or 1$

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

$x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\$

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

$x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2$

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

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2 years ago

Simplify (b-a)U(c-a)?

exis [7]

Answer:

Step-by-step explanation:

3 0

2 years ago

The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si

krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

Minimum = 20
Maximum = 85
Lower quartile = 35
Median = 44
Upper quartile = 58
Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

Minimum = 20 (starting point of the whisker)
Lower quartile = 35 (starting point of the box)
Median = 44 (vertical line in between the box)
Upper quartile = 58 (endpoint of the box)
Maximum = 85 (endpoint of the upper whisker).

Outlier :

Lower boundary = LOWER QUARTILE - (1.5 × IQR)
Upper boundary = UPPER QUARTILE + (1.5 × IQR)
IQR = UPPER QUARTILE - LOWER QUARTILE
IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

7 0

2 years ago