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3 years ago

Which of the following choices is the variance of the sample shown here? 35 37 42 57 61 70

Mathematics

2 answers:

Allushta [10]3 years ago

5 0

Answer:

APEX answer = 205.5

Step-by-step explanation:

viktelen [127]3 years ago

3 0

Answer:

205.5. should be it!

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21 feet to 8 yards write a ratio as a fraction in simplest form without any units

Dmitriy789 [7]

We know, 3 feet = 1 yard.

We have to convert feet to yards to calculate the ratio so that the final answer doesn't have any unit.

Therefore, 21 feet = $\frac{21 feet}{3 feet}yards$ = 7 yards

Thus, the ratio

$\frac{21feet}{8yards} =\frac{7yards}{8yards} =\frac{7}{8}$

The fraction $\frac{7}{8}$ is already in its simplest form.

Therefore, the given ratio as a fraction in the simplest form without any units is $\frac{7}{8}$

3 0

3 years ago

A n =−1+3(n−1) an=−1+3(n−1) what is the 55 term in the sequence

Sindrei [870]

ANSWER

$a_{55}=161$

EXPLANATION

The general term for the sequence is

$a_n=-1+3(n-1)$

To find the 55th term, we have to substitute
$n = 55$
in to the general term and simplify.

This implies that,

$a_{55}=-1+3(55-1)$

$a_{55}=-1+3(54)$

$a_{55}=-1+162$

$a_{55}=161$

Therefore the 55th term is 161.

8 0

3 years ago

There is only three options someone help

Pepsi [2]

Answer:

Answer is Option 2

Step-by-step explanation:

Triangles equal to 180 degrees in total. So it is 55+54+x+74=180

The simplified version that I just wrote is Option 2

7 0

3 years ago

Round 14.354 to the nearest one.

Gnoma [55]

Answer:

Step-by-step explanation: hope this helps :)

3 0

3 years ago

Helpppppppppppppppppppppp..... .......<br><br><br>

morpeh [17]

Answer:

${ \sf{( \sec \theta - \csc \theta)(1 + \tan \theta + \cot \theta) }} \\ = { \sf{( \sec \theta + \tan \theta \sec \theta + \cot \theta \sec \theta) - ( \csc \theta - \csc \theta \tan \theta - \csc \theta \cot \theta)}} \\ = { \sf{( \sec \theta + \sec \theta \tan \theta + \csc \theta) - ( \csc \theta - \sec \theta - \csc \theta \cot \theta)}} \\ = { \sf{ \sec \theta \tan \theta + \csc \theta \cot \theta }} \\ { \bf{hence \: proved}}$

3 0

3 years ago