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erik [133]
3 years ago
14

Maya builds 16 sand castles, Sam builds 7, A dozen sand castles wash away, How many sand castles are left?

Mathematics
1 answer:
bagirrra123 [75]3 years ago
3 0

Answer:

11 castles

Step-by-step explanation:

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Esther estimates that she will need about $8,600 for he first year of 11 point
Elena-2011 [213]

Answer:

$129

Step-by-step explanation:

Esther estimates that she will need about $8,600 for he first year of 11 point

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3 years ago
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If 3x + 3 = -9, then what is 3x + 5 equivalent to?
Anarel [89]

Answer:

- 7

Step-by-step explanation:

Solve for x

3x + 3 = - 9 ( subtract 3 from both sides )

3x = - 12 ( divide both sides by 3 )

x = - 4

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A multiple choice exam consists of 10 questions, each having 5 possible answers. To pass, you must answer at least 6 out of 10 q
prohojiy [21]
You have a 1:2 chance of guessing the right answer, if you have to guess between the two.
6 0
3 years ago
Need help pleaseI was bad at math in school so lwant to learn
aleksklad [387]

The probability of an event is expressed as

Pr(\text{event) =}\frac{Total\text{ number of favourable/desired outcome}}{Tota\text{l number of possible outcome}}

Given:

\begin{gathered} \text{Red}\Rightarrow2 \\ \text{Green}\Rightarrow3 \\ \text{Blue}\Rightarrow2 \\ \Rightarrow Total\text{ number of balls = 2+3+2=7 balls} \end{gathered}

The probability of drwing two blue balls one after the other is expressed as

Pr(\text{blue)}\times Pr(blue)

For the first draw:

\begin{gathered} Pr(\text{blue) = }\frac{number\text{ of blue balls}}{total\text{ number of balls}} \\ =\frac{2}{7} \end{gathered}

For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).

Thus,

\begin{gathered} Pr(\text{blue)}=\frac{number\text{ of blue balls left}}{total\text{ number of balls left}} \\ =\frac{1}{6} \end{gathered}

The probability of drawing two blue balls one after the other is evaluted as

\begin{gathered} \frac{1}{6}\times\frac{2}{7} \\ =\frac{1}{21} \end{gathered}

The probablity that none of the balls drawn is blue is evaluted as

\begin{gathered} 1-\frac{1}{21} \\ =\frac{20}{21} \end{gathered}

Hence, the probablity that none of the balls drawn is blue is evaluted as

\frac{20}{21}

8 0
1 year ago
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