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Ivanshal [37]
3 years ago
14

The period of y = cos x occurs every 2pi units. T/F?

Mathematics
1 answer:
Katyanochek1 [597]3 years ago
8 0
T will be ure answer....

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Lesson Check (4.NF.8.30)<br> 1. Write a mixed number that is equivalent to 16/3
yarga [219]

Answer:

5 1/3

Step-by-step explanation:

Take the numerator and divide by the denominator

16/3 = 5  with 1 remaining

Put the remainder over the deniminator

5 1/3

8 0
3 years ago
Express the fifth roots of unity in standard form a + bi. with 1 + 0i
marishachu [46]

Answer:

For K=0

cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0

For K=1:

cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510

For K=2:

cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587

For K=3:

cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587

For K=4:

cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510

Step-by-step explanation:

Fifth Root is given by:

\sqrt[5]{z}=1+0i

The above equation will become:

z=(1+0i)^5

It can be written as:

z=[cos(0)+isin(0)]^5

|z|=1,

According to De-moivre's Theorem:

z=cos(\frac{0}{5})+isin(\frac{0}{5})\\  z=cos(0)+isin(0)

Now, Fifth Roots of unity in standard form a + bi :

\sqrt[5]{z}=[{cos(0+2\pi k)+isin(0+2\pi k)}]^{1/5}

k=0,1,2,3,4

For K=0

cos(\frac{0+2\pi 0}{5})+isin(\frac{0+2\pi 0}{5})\\cos(0)+isin(0)=1+i0

For K=1:

cos(\frac{0+2\pi 1}{5})+isin(\frac{0+2\pi 1}{5})\\cos(2\pi/5)+isin(2\pi/5)=0.3090+i0.9510

For K=2:

cos(\frac{0+2\pi 2}{5} )+isin(\frac{0+2\pi 2}{5} )\\cos(4\pi/5)+isin(4\pi/5)=-0.809+i0.587

For K=3:

cos(\frac{0+2\pi 3}{5} )+isin(\frac{0+2\pi 3}{5} )\\cos(6\pi/5)+isin(6\pi/5)=-0.809-i0.587

For K=4:

cos(\frac{0+2\pi 4}{5} )+isin(\frac{0+2\pi 4}{5} )\\cos(8\pi/5)+isin(8\pi/5)=0.3091-i0.9510

6 0
3 years ago
At a summer camp there are 40 boys out of 70 campers what is this ratio written as a fraction in simplest form
daser333 [38]

Answer:

4:7

Step-by-step explanation:

6 0
3 years ago
What is the 8th term of the sequence given by an = 3n-5?
Amanda [17]

Answer:

a10 = 25

Step-by-step explanation:

I'm not certain that I have interpreted the question in the way it was intended; however, if I have:

a 10  =  3 (10 )  −  5  =  

30  −  5  =  25

5 0
3 years ago
What number is exactly halfway between 1000 and 1500?
Lunna [17]
the \ number \to \frac{1000+1500}{2}=\frac{2500}{2}\to\boxed{\boxed{1250}}
3 0
3 years ago
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