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2 years ago

PLEASE HELP URGENT WILL MARK BRAINLIEST

Mathematics

2 answers:

tiny-mole [99]2 years ago

8 0

Answer:
90 quarters and four dimes

Bess [88]2 years ago

5 0

Answer:

he had nine quarters and four dimes

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Answer:

1. 38 degrees

2. 38 degrees

Step-by-step explanation:

It tells you that angle 1 is 38 degrees, and they are supplementary angles, which means angle 2 is also 38 degrees.

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2 years ago

Find the common difference of the arithmetic sequence 4, 1, -2, ...

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2 years ago

120 inch board cut in 8 inch

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15, 8 inch boards

Step-by-step explanation:

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2 years ago

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3 years ago

If f(x)= sqrtx-3 and g(x)=1-x^2, then what do you notice about the domain of (fxg)(x)?

Oduvanchick [21]

Answer:

$x\geq0$ if $f(x)=\sqrt{x}-3$

$x\geq3$ if $f(x)=\sqrt{x-3}$

Step-by-step explanation:

If $f(x)=\sqrt{x}-3$ then the domain of f(x) is all positive real numbers. This is $x\geq0$

On the other hand the domain of g(x) would be all real numbers because it is a polynomial function

Therefore

$(f*g)(x) = f(x)*g(x)\\\\(f*g)(x) =(\sqrt{x}-3)*(1-x^2)$

$(f*g)(x) =\sqrt{x}-x^2(\sqrt{x})-3+3x^2$

Then the domain of $f(x) *g(x)$ will be the same domain of $f(x)$

All positive real numbers, $x\geq0$ or x ∈ [0, ∞)

-----------------------------------------------------------------------------------------------

If f(x) = $\sqrt{x-3}$ then the domain of f(x) is

$x-3\geq0\\\\x\geq3$

Therefore

$(f*g)(x) = f(x)*g(x)\\\\(f*g)(x) =(\sqrt{x-3})*(1-x^2)$

$(f*g)(x) =\sqrt{x-3}-x^2(\sqrt{x-3})$

Then the domain of $f(x) *g(x)$ will be the same domain of $f(x)$

$x\geq3$ or x ∈ [3, ∞)

3 0

3 years ago

Read 2 more answers