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kicyunya [14]
3 years ago
9

Find m∠DEC (the picture is not drawn to scale).

Mathematics
1 answer:
pochemuha3 years ago
8 0

Answer:

M∠DEC equals 123º.

Step-by-step explanation:

The sum of a triangle's three angles always equal 180º. The exterior angle, x, equals the two non-adjacent interior angles.

180 - {(x - 45)+(x - 12)} = m∠DEC

m∠DEC + x = 180

<u>(x - 45) + (x - 12) = x</u>

Solving for x:

(x - 45) + (x - 12) = x

x - 45 + x - 12 = x                             Remove parenthesis

2x - 57 = x                                       Combine like terms

2x = x + 57                                      Add 57 to both sides

<u>x = 57</u><u>                                             Subtract x from both sides</u>

Finding m∠D:

x - 45 = ?

<u>57 - 45 = </u><u>12º                                          </u>

Finding m∠C:

x - 12 = ?

<u>57 - 12 = </u><u>45º                                           </u>

<em>** </em><em>(Checking x: 12 + 45 = 57) </em><em>**</em>

<em>Finding </em>m∠DEC:

AC is a straight line, and because straight lines are equivalent to 180º, we subtract 57 from 180:

180 - 57 = 123º

Hope this helps,

❤<em>A.W.E.</em><u><em>S.W.A.N.</em></u>❤

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Answer:

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Step-by-step explanation:

6(4a+1)

24a+6

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24a+6=12a

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3 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
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Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

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