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Olin [163]
3 years ago
7

671 divided by 7 need answer with picture please

Mathematics
1 answer:
Kaylis [27]3 years ago
6 0

Answer:

95.8571428571 is my workout answer I get the answer I said how many times 7 could go into 671

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enyata [817]
14^10. Minus the powers 15 - 10
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2 years ago
One leg of a right triangle has a length of 5m. The other sides have lengths that are consecutive integers. Find these lengths.
pickupchik [31]

The lengths of the other two sides of the right triangle are 12 and 13

<h3>Pythagorean theorem </h3>

From the question, we are to determine the lengths of the other sides of the triangle

From the given information,

The other sides have lengths that are consecutive integers

Thus,

If the length of the other side is x

Then,

The hypotenuse will be x + 1

By the <em>Pythagorean theorem</em>, we can write that

(x+1)² = x² + 5²

(x+1)(x+1) = x² + 25

x² + x + x + 1 = x² + 25

x² - x² + x + x = 25 - 1

2x = 24

x = 24/2

x = 12

∴ The other leg of the right triangle is 12

Hypotenuse = x + 1 = 12 + 1 = 13

Hence, the lengths of the other two sides are 12 and 13

Learn more on Pythagorean theorem here: brainly.com/question/4584452

#SPJ1

7 0
2 years ago
A guitar string has a number of frequencies at which it will naturally vibrate when it is plucked. These natural frequencies are
AlladinOne [14]

Answer:

Step-by-step explanation:

4 0
2 years ago
On Mars the acceleration due to gravity is 12 ft/sec^2. (On Earth, gravity is much stronger at 32 ft/sec^2.) In the movie, John
insens350 [35]

Solution :

Given initial velocity, v= 48 ft/s

Acceleration due to gravity, g = $12\ ft/s^2$

a). Therefore the maximum height he can jump on Mars is

     $H_{max}=\frac{v^2}{2g}$

     $H_{max} = \frac{(48)^2}{2 \times 12}$

               = 96 ft

b). Time he can stay in the air before hitting the ground is

   $T=\frac{2v}{g}$

  $T=\frac{2 \times 48}{12}$

     = 8 seconds

c).  Considering upward motion as positive direction.

     v = u + at

We find the time taken to reach the maximum height by taking v = 0.

     v = u + at

     0 = 16 + (12) t

     $t=\frac{16}{12}$

        $=\frac{4}{3} \ s$

We know that, $S=ut + \frac{1}{2}at^2$

Taking t =  $=\frac{4}{3} \ s$  , we get

$S=16 \times\frac{4}{3} + \frac{1}{2}\times(-12) \times \left(\frac{4}{3}\right)^2$

$S=\frac{32}{3}$  feet

Thus he can't reach to 100 ft as it is shown in the movie.

d). For any jump whose final landing position will be same of the take off level, the final velocity will be the initial velocity.

Therefore final velocity is = -16 ft/s

3 0
3 years ago
Jack deposited $1,400 in his bank account. After 3 years, the account is worth $1,694. Find the simple interest rate the account
fenix001 [56]

Answer:

D. 7%

Step-by-step explanation:

5 0
2 years ago
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