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Nostrana [21]
3 years ago
5

What is the sign of 3x y3xy3, x, y when x>0x>0x, is greater than, 0 and y<0y<0y, is less than, 0?

Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

B ) Negative

Step-by-step explanation:

Given the expression 3xy

when x>0 and y<0

The value of the expression 3xy will be negative.

This is because the product of a positive and negative number will always be negative.

For illustration,

Let x=5>0 and y=-5<0

3xy=3(5)(-5)=-75

NOTE:

-X-=+\\-X+=-\\+X+=+

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kvasek [131]

Answer:

w= -27

Step-by-step explanation:

w/3 = -9

w = 3 * -9 = -27

7 0
3 years ago
Hannah is at the supermarket to buy carrots and potatoes. If she buys 2 pounds of carrots and 3 pounds of potatoes, it will cost
zhenek [66]

Answer:

Carrots cost $ 1.75 a pound which is more than potatoes cost.

Step-by-step explanation:

Let,

Carrots cost $ x per pound and potatoes cost $ y per pound.

Buying 2 pounds of carrots  and 3 pounds of potatoes will cost her

$ (2\times x + 3\times y)

and

Buying 4 pounds of carrots and 4 pounds of potatoes will cost her

$ (4\times x + 4\times y)

According to the question,

(2\times x + 3\times y) = 8-----(1)

(4\times x + 4\times y) = 13-----(2)

multiplying (1) by 2 we get,

(4\times x + 6\times y) = 16-----(3)

Deducting (2) from (3) we get,

2\times y = 3

⇒ y = \frac{3}{2} = 1.5------------------(4)

Putting value of y in (1) we get,

(2\times x = 8 - 3\times 1.5) = 3.5

⇒  x =\frac{3.5}{2} = 1.75 ------------(5)

8 0
3 years ago
How to find a book in brainly​
Lisa [10]

Step-by-step explanation:

in the textbook column you can find the search symbol

there you can search for the hook you want

hope this is what you wanted

3 0
3 years ago
A=1/2h (b+c) solve for b
Illusion [34]
A=1/2h(b+c)
times both sides by 2/1
2A=h(b+c)
divide both sides by h
\frac{2A}{h}=b+c
minus c from both sides
\frac{2A}{h}-c=b

8 0
3 years ago
Prove that 1/sec0-tan0= sec0+tan0
Leviafan [203]

Answer:

Step-by-step explanation:

\text{LHS}=\frac{1}{\sec \theta-\tan \theta}\\=\frac{\sec \theta+\tan \theta}{(\sec \theta-\tan \theta)(\sec \theta+\tan \theta)}\\=\frac{\sec \theta+\tan \theta}{\sec^{2} \theta-\tan^{2} \theta}\\=\frac{\sec \theta+\tan \theta}{1}\\=\sec \theta+\tan \theta\\=\text{RHS}

7 0
2 years ago
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