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Komok [63]
3 years ago
14

Simplify square root 3y diviede by square root of y​

Mathematics
1 answer:
Nataly [62]3 years ago
5 0

Answer:

Step-by-step explanation:

√3y/√y

= √(3y/y)

= √3

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Name two solutions for each inequality.
ahrayia [7]
So,

#1: n  \geq 3 \frac{11}{16} + 4 \frac{1}{2}

Convert to like improper fractions.
n  \geq  \frac{59}{16} +  \frac{72}{16}

Add.
n  \geq  \frac{131}{16}\ or\ 8 \frac{3}{16}

So, one solution could be 8 \frac{3}{16}.

Another solution could by 9.  There is also 10, 11, 12, etc., and all numbers in between.


#2: k \ \textless \  6  \frac{2}{5} * 15

Convert into improper fraction form.
k \ \textless \ \frac{32}{5} * 15

Multiply.
\frac{(2^5)(3)(5)}{5}

Cross-cancel, and we have our final result.
(2^5)(3) = 96
k < 96

96 is not a solution.

95 is a solution.

So is 94, 93, 92, etc, and all numbers in between.
6 0
3 years ago
Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions
quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of v_0 and F_2 be the component normal to v_0.

Since, |v_0| = 1,

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, v_0 = \left

From figure,

|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3

We know that the direction of F_1 is opposite of the direction of v_0, so we have

$F_1 = -5\sqrt3 v_0$

    $=-5\sqrt3 \left$

    $= \left$

The unit vector in the direction normal to the plane, v_1 has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5

∴  F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>

                   $=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

           $= = F$

3 0
2 years ago
5miles from 16miles what is the increase
Mariulka [41]
The increase in miles would be 11 miles
4 0
3 years ago
Find the circumference of a circle with radius, r = 10.5m.Give your answer in terms of π<br> .
forsale [732]

Answer:

Circumference of circle =2πr=2π×10.5=21πm

Step-by-step explanation:

8 0
3 years ago
Simplify 7.32a+2.1∙(2.7−18a)
tresset_1 [31]
7.32a + 2.1(2.7 -18a)
7.32a + 5.67 - 37.8a (multiply 2.1 to 2.7 and 18a)
5.67 - 30.48a (combine 7.32a and -37.8a since they are like terms)
6 0
3 years ago
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