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cupoosta [38]
2 years ago
9

You can choose from the following 15, 16, 24, -88, 75, -62, 151, 88, 1, 30, -5 Also thank you in advance I don't know why I don'

t get this one so please explain if possible!

Mathematics
2 answers:
saveliy_v [14]2 years ago
8 0

Answer:

-88

Step-by-step explanation:

whoever deleted my answer thanks a lot

maxonik [38]2 years ago
3 0
-88 = 8+q^3 + (12-4^2+7) -10^2
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Answer:

what are the answer choices?

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Find the value of x<br> I’ll mark the BRAINEST
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The answer is x=45.
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Can someone explain what geometric sequences are?
Fed [463]

Explanation:

A sequence is a list of numbers.

A <em>geometric</em> sequence is a list of numbers such that the ratio of each number to the one before it is the same. The common ratio can be any non-zero value.

<u>Examples</u>

  • 1, 2, 4, 8, ... common ratio is 2
  • 27, 9, 3, 1, ... common ratio is 1/3
  • 6, -24, 96, -384, ... common ratio is -4

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<u>General Term</u>

Terms of a sequence are numbered starting with 1. We sometimes use the symbol a(n) or an to refer to the n-th term. The general term of a geometric sequence, a(n), can be described by the formula ...

  a(n) = a(1)×r^(n-1) . . . . . n-th term of a geometric sequence

where a(1) is the first term, and r is the common ratio. The above example sequences have the formulas ...

  • a(n) = 2^(n -1)
  • a(n) = 27×(1/3)^(n -1)
  • a(n) = 6×(-4)^(n -1)

You can see that these formulas are exponential in nature.

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<u>Sum of Terms</u>

Another useful formula for geometric sequences is the formula for the sum of n terms.

  S(n) = a(1)×(r^n -1)/(r -1) . . . . . sum of n terms of a geometric sequence

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  S = a(1)/(1-r)

8 0
3 years ago
In an arithmetic sequence, t4 + t5 + t6 = 300, and t15 +t16+ t17 = 201. Find t18.
stiks02 [169]
In an arithmetic sequence:
Tn=t₁+(n-1)d

t₄=t₁+(4-1)d=t₁+3d
t₅=t₁+(5-1)d=t₁+4d
t₆=t₁+(6-1)d=t₁+5d

t₄+t₅+t₆=(t₁+3d) +(t₁+4d)+(t₁+5d)=3t₁+12d

Therefore:
3t₁+12d=300    (1)


t₁₅=t₁+(15-1)d=t₁+14d
t₁₆=t₁+(16-1)d=t₁+15d
t₁₇=t₁+(17-1)d=t₁+16d

t₁₅+t₁₆+t₁₇=(t₁+14d)+(t₁+15d)+(t₁+16d)=3t₁+45d

Therefore:
3t₁+45d=201    (2)

With the equations (1) and (2) we make an system of equations:

3t₁+12d=300
3t₁+45d=201

we can solve this system of equations by reduction method.

  3t₁+12d=300
-(3t₁+45d=201)
-----------------------------
       -33d=99      ⇒d=99/-33=-3

3t₁+12d=300
3t₁+12(-3)=300
3t₁-36=300
3t₁=300+36
3t₁=336
t₁=336/3
t₁=112

Threfore:

Tn=112+(n-1)(-3)
Tn=112-3n+3
Tn=115-3n

Now, we calculate T₁₈:

T₁₈=115-3(18)=115-54=61

Answer: T₁₈=61




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0,3 3,3 2,3 and 1,2 (from A to D)
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