Answer:
If this is what your looking for, the answer may be:
-4y + 12
Hope this helps!
To prove a similarity of a triangle, we use angles or sides.
In this case we use angles to prove
∠ACB = ∠AED (Corresponding ∠s)
∠AED = ∠FDE (Alternate ∠s)
∠ABC = ∠ADE (Corresponding ∠s)
∠ADE = ∠FED (Alternate ∠s)
∠BAC = ∠EFD (sum of ∠s in a triangle)
Now we know the similarity in the triangles.
But it is necessary to write the similar triangle according to how the question ask.
The question asks " ∆ABC is similar to ∆____. " So we find ∠ABC in the prove.
∠ABC corressponds to ∠FED as stated above.
∴ ∆ABC is similar to ∆FED
Similarly, if the question asks " ∆ACB is similar to ∆____. "
We answer as ∆ACB is similar to ∆FDE.
Answer is ∆ABC is similar to ∆FED.
Answer:
C
Step-by-step explanation:
Answer:
the answer would be p= -4
13-3p = -5(3+2p)
13-3p = -15-10p
13 = -15-7p
28 = -7p
p = -4
X/13
Quotient means divide. So you will make a fraction. On the top goes x and on the bottom is 13
