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MatroZZZ [7]
3 years ago
9

Helllpppp meeeee plsssssss

Mathematics
1 answer:
Ainat [17]3 years ago
7 0

Answer:

The inequality \frac{8}{4}\:  is true.

Step-by-step explanation:

Given

\frac{8}{5}

FALSE

Reason: 8/5 or 1.6 is greater than 9/10 or 0.9  

1>\frac{6}{5}

FALSE

Reason: 1 is smaller than 6/5 or (1.1)

\frac{5}{2}

converting mixed number to improper fraction

\frac{5}{2}

FALSE

Reason: 5/2 can not be less than 5/2

\frac{8}{4}\:

2

TRUE

Reason: 2 is indeed smaller than 5/2 or 5.2        ∵ 5/2 = 2.5

Therefore, inequality \frac{8}{4}\:  is true.

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3 years ago
To repair computers, Computer
NeTakaya
Difference in base price — $200–$125=$75
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3 0
2 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
pogonyaev

By using the general equation for a circle, we will see that the correct options are:

  • 1) This is a circle centered at (-3, - 5) with a radius of 4 units.
  • 2) The center is (-3, 5) and the radius is 2 units.
  • 3) The center is (3, 5) and the radius is 2 units.
  • 4) This is a circle centered at (3, - 5) with a radius of 4 units.

<h3>How to write a circle equation?</h3>

For a circle of radius R and center (a, b), the equation is given by:

(x - a)^2 + (y - b)^2 = R^2

With that in mind, if we look at the first equation:

(x + 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (-3, - 5) with a radius of 4 units.

For the second equation:

(x + 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (-3, 5) and the radius is 2 units.

The third equation is:

(x - 3)^2 + (y - 5)^2 = 4 = 2^2

The center is (3, 5) and the radius is 2 units.

The fourth equation is:

(x - 3)^2 + (y + 5)^2 = 16 = 4^2

This is a circle centered at (3, - 5) with a radius of 4 units.

If you want to learn more about circles, you can read:

brainly.com/question/14283575

7 0
2 years ago
Find the sum of the first 50 positive even integers.
adell [148]
2250
50*(2+100)/2
50*102/2
50*51
2250
7 0
3 years ago
Find all points having an x-coordinate of 2 whose distance from the point (-1,-2) is 5
mariarad [96]
The\ equation\ of\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\where\ (a;\ b)\ -the\ coordinates\ of\ the\ center;\ r-the\ radius\\-----------------------------\\(-1;-2)-the\ center\ of\ the\ circle\\r=5\\\\The\ equation:(x+1)^2+(y+2)^2=5^5\\\\Put\ x=2\ to\ the\ equation:\\\\(2+1)^2+(y+2)^2=25\\3^2+(y+2)^2=25\\9+(y+2)^2=25\\(y+2)^2=25-9\\(y+2)^2=16\iff y+1=\pm\sqrt{16}\\\\y+1=-4\ or\ y+1=4\ \ \ \ \ |subtract\ 1\ from\ both \sides\\y=-5\ or\ y=3\\\\Answer:(2;-5)\ and\ (2;\ 3).
5 0
3 years ago
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