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Kay [80]
3 years ago
13

5y + 3 > -7 + 13 how do i do this

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0
5y + 3 > -7 + 13

First add -7 + 13 = 6

5y + 3 > 6

Subtract 3 from both sides

5y + 3 -3 > 6 - 3

5y > 3

Divide both sides by 5

5y/5 > 3/5

y > 3/5
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What is Pythagoras Theorem ?
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Pythagoras Theorem is the way in which you can find the missing length of a right angled triangle.
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Pythagoras is in the form of;
a<em><u /></em>²+b²=c²
However, it can also be written in the form of c²=a²+b²
In order to find the hypotenuse, you will have the length of two sides, for example, these could be 3 and 4.
As 'C' is always the hypotenuse, you have to work out the two other lengths, and you do this by squaring the numbers.
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As you're looking for C, you've got to add these together
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As a²+b²=c², this means that the answer for C is the square root of 25.
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5 0
3 years ago
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{ vowels in the word ALGEBRA}​
zheka24 [161]

Answer:

3 counting ALL VOWELS, or, 2 counting no double ups

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7 0
2 years ago
How many solutions does this equation have? -3 – 7t = -7t - 3
nignag [31]

Answer:

3)infinitely many solution

Step-by-step explanation:

-3 - 7t = -7t - 3

-7t + 7t = -3 + 3

0 = 0

if there is same number on both side it have infinitely many solution.

hope u like it ‍❤️‍❤️‍‍❤️‍

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3 years ago
15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

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3 years ago
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