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Tanzania [10]
2 years ago
8

Circle theorems please help

Mathematics
1 answer:
suter [353]2 years ago
6 0

Answer:

n = 28°

Step-by-step explanation:

The angle at the centre is twice the angle on the circle subtended on the same arc.

Also angles subtended on the same arc are congruent , thus

m = n

Then

35 + m = \frac{1}{2} (98 + n ) ← multiply both sides by 2 to clear the fraction

70 + 2m = 98 + n , but since m = n, then

70 + 2m = 98 + m ( subtract m from both sides )

70 + m = 98 ( subtract 70 from both sides )

m = 14 and n = 28

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borishaifa [10]

Answer:

true

The wording does not quite mean anything,

but what I think was meant to ask is

"if we use some parts of two triangles to prove they are congruent,

can we then use that to prove that

a pair of corresponding parts not used before are congruent?"

The answer is

Yes, of course,

Corresponding Parts of Congruent Triangles are Congruent,

which teachers usually abbreviate as CPCTC.

For example, if we find that

side AB is congruent with side DE,

side BC is congruent with side EF, and

angle ABC is congruent with angle DEF,

we can prove that triangles ABC and DEF are congruent

by Side-Angle-Side (SAS) congruence.

We then, by CPCTC, can conclude that other pairs of corresponding parts are congruent:

side AB is congruent with side DE,

angle BCA is congruent with angle EFD, and

angle CAB is congruent with angle FDE.

It was possible (by CPCTC) to prove those last 3 congruence statements,

after proving the triangles congruent.

The expected answer is FALSE.

Step-by-step explanation:

4 0
3 years ago
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dybincka [34]

Answer:

C. $80

Step-by-step explanation:

A. $70

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Answer:

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Elis [28]

Answer:

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Step-by-step explanation:

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