3 years ago

What is the solution of the equation when solved over complex numbers? x^2+27=0

1 answer:

7 0

${x}^{2} + 27 = 0 \\ {x}^{2} = - 27 \\ x = + - \sqrt{ - 27} \\ x = + - \sqrt{27 \times ( - 1) }$
$x = + - 3 \sqrt{3} \times \sqrt{ - 1}$
$x = + - 3 \sqrt{3} i$

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