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cluponka [151]
3 years ago
9

What is the solution of the equation when solved over complex numbers? x^2+27=0

Mathematics
1 answer:
Papessa [141]3 years ago
7 0

{x}^{2}  + 27 = 0 \\  {x}^{2}  =  - 27 \\ x =   +  - \sqrt{ - 27}  \\ x =  +  -  \sqrt{27 \times ( - 1) }
x =  +  - 3 \sqrt{3}  \times  \sqrt{ - 1}
x  =  +  - 3 \sqrt{3} i
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