What is the solution of the equation when solved over complex numbers? x^2+27=0
1 answer:
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Answer:
Option A
Step-by-step explanation:
By applying Pythagoras theorem in ΔABC,
(Hypotenuse)² = (Leg 1)² + (Leg 2)²
AC² = AB² + BC²
AC² = 6² + 5²
AC =
Similarly, by applying Pythagoras theorem in ΔACD,
AD² = AC² + CD²
(10)² = + x²
x² = 100- 61
x² = 39
x = √(39)
Option A will be the answer.
Answer:
See explanation below for further details.
Step-by-step explanation:
A rational consist of two real numbers such that:
If c is a polynomial with a certain grade, then, both the numerator and the denominator must be also polynomials and the grade of the numerator must be greater than denominator.
If c is linear function, that is, a first order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.
Example:
If and
, then:
If c is a quadratic function, that is, a second order polynomial, then a must be a (n+1)-th polynomial and b must be a n-th polynomial.
Example
If and
, then:
But if c is an exponential, both the numerator and the denominator must be therefore exponential function and grade of each exponential function must different to the other.
Example
If and
, then:
Otherwise, c would be equal to a constant function, that is, a polynomial with a grade 0.
If and
, then:
Example
It is worth to add that exponential functions can be a linear combination of single exponential function, similar to polynomials.
Example