How many terms are in the algebraic expression 3x^2+4y-1

Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

KengaRu [80]

Answer:

Using the ratio and proportion method, we find that on an average 1.875 rooms can be painted per gallon.

Step-by-step explanation:

Concept: Use the method of ratio and proportion. Given that for 2/5 gallons of paint, we can paint 3/4 of rooms. So, for one gallon of paint, divide 2/5 by 3/4.

2/5 gallons of paint = 3/4 rooms

1 gallon of paint = $\frac{\frac{3}{4} }{\frac{2}{5} } = \frac{15}{8} =1.875$ rooms

So, on an average they can paint 1.875 rooms per gallon.

For more explanation, refer the following link

brainly.com/question/11243787

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8 0

2 years ago

Estimate The problem <br><br> 2,731÷31

Vedmedyk [2.9K]

Answer:

your answer should be 90

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Tara earns $9 for each dog she walks. She walks 10 dogs an hour. After walking dogs for 4 hours, how much money will Tara have e

solong [7]

Answer: $360

Step-by-step explanation:

In one hour, she makes $9 * 10 dogs = $90.

In 4 hours, we simply multiply that by 4 to get $90 * 4 = $360 total

4 0

2 years ago

Read 2 more answers

A man traveled 1/3 of the distance between

VladimirAG [237]

Answer: 2 hours 15 minutes

Step-by-step explanation:

3/4 of an hour times 3 will be 9/4; each fourth is 15 minutes. 9 times 15 is 135 minutes, which is 2 hours and 15 minutes

7 0

3 years ago

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Write out the first four terms of the series to show how the series starts. Then find the sum of the series or show that it dive

Nostrana [21]

Answer:

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$ = 14.25

Step-by-step explanation:

We know that

Sum of convergent series is also a convergent series.

We know that,

$\sum_{k=0}^\infty a(r)^k$

If the common ratio of a sequence |r| <1 then it is a convergent series.

The sum of the series is $\sum_{k=0}^\infty a(r)^k=\frac{a}{1-r}$

Given series,

$\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

$=(9+3)+(\frac97+\frac35)+(\frac9{7^2}+\frac3{5^2})+(\frac9{7^3}+\frac3{5^3})+.......$

The first four terms of the series are

$(9+3),(\frac97+\frac35),(\frac9{7^2}+\frac3{5^2}),(\frac9{7^3}+\frac3{5^3})$

Let

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$ and $t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

Now for $S_n$ ,

$S_n=9+\frac97+\frac{9}{7^2}+\frac9{7^3}+.......$

$=\sum_{n=0}^\infty9(\frac 17)^n$

It is a geometric series.

The common ratio of $S_n$ is $\frac17$

The sum of the series

$S_n=\sum_{n=0}^\infty \frac{9}{7^n}$

$=\frac{9}{1-\frac17}$

$=\frac{9}{\frac67}$

$=\frac{9\times 7}{6}$

=10.5

Now for $t_n$

$t_n= 3+\frac35+\frac{3}{5^2}+\frac3{5^3}+.......$

$=\sum_{n=0}^\infty3(\frac 15)^n$

It is a geometric series.

The common ratio of $t_n$ is $\frac15$

The sum of the series

$t_n=\sum_{n=0}^\infty \frac{3}{5^n}$

$=\frac{3}{1-\frac15}$

$=\frac{3}{\frac45}$

$=\frac{3\times 5}{4}$

=3.75

The sum of the series is $\sum_{n=0}^\infty \frac9{7^n}+\frac{3}{5^n}$

= $S_n+t_n$

=10.5+3.75

=14.25

4 0

3 years ago