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4 years ago

What is the fifth term of a number pattern that begins with 32 and adds 5? A. 47 B. 42 C. 52 D. 57

Mathematics

1 answer:

artcher [175]4 years ago

8 0

The answer you want would be C.52

Reason: 32+5= 37 that is the 1st and 2nd term. 37+5=42 thatis the 3rd term. 42+5=47 that's the 4th term. And 47+5=52 that's the 5th term.

Hope it helps!!

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2x^2-3x-9 please help

Romashka-Z-Leto [24]

Im assuming you mean 2x^2-3x-9=0 ?
If so, you have to factorise the equation
(2x-3) (x+3) = 0

2x - 3 = 0
2x = 3
x = 1.5

x + 3 = 0
x = -3

x is either 1.5 or -3

8 0

4 years ago

Read 2 more answers

If m< BOE = 130 degrees and m< cob = 80 degrees

hjlf

Answer:

then what?

Step-by-step explanation:

do we have to find the angle?

all I know is every right triangle is equal to 90°

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3 years ago

4 2/3 divide by 1 2/3

sladkih [1.3K]

Answer:

14/5

Step-by-step explanation:

I'd suggest rewriting both mixed numbers as improper fractions. Then we'd have:

14/3 and 5/3

Dividing 14/3 by 5/3 is equivalent to dividing 14 by 5, since the denominators are the same (3).

Quotient is 14/5.

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4 years ago

Are all functions linear or exponential? Or does it go like, “all linear or exponentials are functions”?

Alex_Xolod [135]

The second one is correct

3 0

3 years ago

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as

mamaluj [8]

Answer:

The farmer have at first 202 chickens.

Step-by-step explanation:

Given:

A farmer had twice as many chickens as ducks on his farm. After he sold 166 chickens and ducks, he had half as many chickens as ducks left.

Now, to find the chickens farmer have at first.

Let the chickens be $x.$

And, the ducks be $y.$

As, the farmer had twice as many chickens as ducks on his farm.

So, $x=2y$ ......(1)

As, given the farmer after selling 166 chickens and ducks, he had half as many chickens as ducks left.

According to question:

$x-166=(y-29)\times \frac{1}{2}$

$x-166=\frac{y-29}{2}$

Substituting the value of $x$ from equation (1) we get:

$2y-166=\frac{y-29}{2}$

By cross multiplying we get:

$4y-332=y-29$

Adding both sides 332 we get:

$4y=y+303$

Subtracting both sides by $y$ we get:

$3y=303$

Dividing both sides by 3 we get:

$y=101.$

Now, to get the number of chickens substituting the value of $y$ in equation (1):

$x=2y\\\\x=2\times 101\\\\x=202.$

Therefore, the farmer have at first 202 chickens.

7 0

3 years ago