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stich3 [128]
2 years ago
6

The equation that models the current water temperature t of the swimming pool is t -6=78 which best describes the error made whe

n solving for the current temperature

Mathematics
1 answer:
Maksim231197 [3]2 years ago
6 0

Answer:

The same number was not added to both sides.

Step-by-step explanation:

The same number was not added to both sides.

In line 2,  6 was added to the left side  and 78 was added to the right side.

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What is the greatest common factor of the terms 14c to the second power D and 42 C to the third power d
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Answer:


Step-by-step explanation:

To find the GCF we factor all the given terms and then find the Greatest Common Factor from both ,


So , The given two terms can be given by

14c^2d = 2.7.c.c.d\\42c^3d =2.3.7.c.c.c.d\\

Here common numbers that are in both are

2.7.c.c.d

so GCF= 14c^2d

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Which of the following show a geometric series? Select all that apply.
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A, D, and E, are geometric series
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Which equation represents a proportional relationship? A) y = 3x 8 B) y = 3 8x C) y = 3x 8 + 1 D) y = 3 8x + 1
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Reducing fractions 43/64
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The table displays the number of students in each grade at Richmond High School who will or will not be attending the amusement
Pani-rosa [81]

Answer:

P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

Step-by-step explanation:

We are given a joint probability table.

There are four different graders in a school

1. Grade Ninth

2. Grade Tenth

3. Grade Eleventh

4. Grade Twelfth

Field trip refers to the students who will attending the amusement park field trip.

No field trip refers to the students who will not be attending the amusement park field trip.

We want to find out the probability that the selected student is an eleventh grader given that the student is going on a field trip.

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)}

Where P(eleventh and FT) is the probability of students who are in eleventh grade and will be going to field trip

P(eleventh\:  and \: FT) = \frac{13}{92}  \\\\P(eleventh \:  and \: FT) = 0.1413

Where P(FT) is the probability of students who will be going to field trip

P(FT) = \frac{12}{92} + \frac{9}{92} + \frac{13}{92} + \frac{19}{92}\\\\P(FT) = 0.1304 + 0.0978 + 0.1413 + 0.2065\\\\P(FT) = 0.576 \\\\

So the required probability is

P( eleventh\: \: |\: \: FT)= \frac{P( eleventh\: \: and \: \: FT)}{P(FT)} \\\\P( eleventh\: \: |\: \: FT)= \frac{0.1413}{0.576} \\\\P( eleventh\: \: |\: \: FT)=  0.2453 \\\\P( eleventh\: \: |\: \: FT)=  24.53\% \\\\

6 0
3 years ago
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