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photoshop1234 [79]
3 years ago
5

Please help!! Worth 28 points if you can solve it correctly and proof on paper

Mathematics
1 answer:
OlgaM077 [116]3 years ago
3 0

8p + 3q - 18 when p = 1/2 and q = 7

You are given that p is equal to 1/2 and q is equal to 7, so plug these values into p and q in the expression to find your answer.

Rewrite your expression to include the values of p and q plugged in. Your expression should look like:

8(1/2) + 3(7) - 18

According to PEMDAS, multiplication should be solved first before doing subtraction, so multiply 8 by 1/2 and 3 by 7. Rewrite your expression; your expression should look like this:

4 + 21 - 18

According to PEMDAS, addition and subtraction should be solved from left to right; they are not prioritized. So solve the expression from left to right and then you will have your answer.

4 + 21 = 25

25 - 18 = 7

Your answer is 7.

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Select all the conditions for which it is possible to construct a triangle. (7.G.1.2) Group of answer choices a. A triangle with
saw5 [17]

Answer:

  b, d, e, f

Step-by-step explanation:

Here are the applicable restrictions:

  • The sum of angles in a triangle is 180°, no more, no less.
  • The sum of the lengths of the two shortest sides exceeds the longest side.
  • When two sides and the angle opposite the shortest is given, the sine of the given angle must be at most the ratio of the shortest to longest sides.

a. A triangle with angle measures 60°, 80°, and 80° (angle sum ≠ 180°, not OK)

b. A triangle with side lengths 4 cm, 5 cm, and 6 cm (4+5 > 6, OK)

c. A triangle with side lengths 4 cm, 5 cm, and 15 cm (4+5 < 15, not OK)

d. A triangle with side lengths 4 cm, 5 cm, and a 50° angle across from the 4 cm side (sin(50°) ≈ 0.766 < 4/5, OK)

e. A triangle with angle measures 30° and 60°, and an included 3 cm side length (OK)

f. A triangle with angle measures 60°, 20°, and 100° (angle sum = 180°, OK)

_____

<em>Additional comment</em>

In choice "e", two angles and the side between them are specified. As long as the sum of the two angles is less than 180°, a triangle can be formed. The length of the side is immaterial with respect to whether a triangle can be made.

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The congruence postulates for triangles are ...

  SSS, SAS, ASA, AAS, and HL

These essentially tell you the side and angle specifications necessary to define <em>a singular triangle</em>. As we discussed above, the triangle inequality puts limits on the side lengths specified in SSS. The angle sum theorem puts limits on the angles when only two are specified (ASA, AAS).

In terms of sides and angles, the HL postulate is equivalent to an SSA theorem, where the angle is 90°. In that case, the angle is opposite the longest side (H). In general, SSA will specify a singular triangle when the angle is opposite the <em>longest</em> specified side, regardless of that angle's measure. However, when the angle is opposite the <em>shortest</em> specified side, the above-described ratio restriction holds. If the sine of the angle is <em>less than</em> the ratio of sides, then <em>two possible triangles are specified</em>.

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