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photoshop1234 [79]

3 years ago

11

Which expression is equivalent to (84+16)

2 answers:

LuckyWell [14K]3 years ago

6 0

Answer:

(85 + 15) is equivalent

Step-by-step explanation:

Not sure what you are asking 100%

miv72 [106K]3 years ago

4 0

Answer:

4(21 + 4)

2(42 + 8)

Step-by-step explanation:

4(21 + 4) - simplify by greatest common

2(42 + 8)simplify by least common

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Can anyone help? i’ll mark brainliest

dimulka [17.4K]

|4x + 4| = 15

First, let's get rid of the absolute value signs to get the first solution.

4x + 4 = 15

Subtract 4 from both sides

4x = 11

Divide each side by 4

x = 11/4 or 2.75

Now, let's get the solution by changing 15 to -15.

4x + 4 = -15

Subtract 4 from both sides

4x = -19

Divide both sides by 4

x = -19/4 or -4.75

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4 years ago

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I am 69% done in one of my classes just wanna say that I'm almost done so before I finish I just wanted to let y'all know that.

GaryK [48]

Answer: Thats goated man

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

A basketball player makes a free throw 82.6% of the time. The player attempts 5 free throws. Use a histogram of the binomial dis

DiKsa [7]

Answer:

The most likely outcome is exactly 4 free throws

Step-by-step explanation:

Given

$n = 5$ --- attempts

$p = 82.6\%$ ---- probability of a successful free throw

$p = 0.826$

Required

A histogram to show the most likely outcome

From the question, we understand that the distribution is binomial.

This is represented as:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

For x = 0 to 5, where x represents the number of free throws; we have:

$P(X = x) = ^nC_x * p^x * (1 - p)^{n-x}$

$P(X = 0) = ^5C_0 * 0.826^0 * (1 - 0.826)^{5-0}$

$P(X = 0) = ^5C_0 * 0.826^0 * (0.174)^{5}$

$P(X = 0) = 1 * 1 * 0.000159 \approx 0.0002$

$P(X = 1) = ^5C_1 * 0.826^1 * (1 - 0.826)^{5-1}$

$P(X = 1) = ^5C_1 * 0.826^1 * (0.174)^4$

$P(X = 1) = 5 * 0.826 * 0.000917 \approx 0.0038$

$P(X = 2) = ^5C_2 * 0.826^2 * (1 - 0.826)^{5-2}$

$P(X = 2) = ^5C_2 * 0.826^2 * (0.174)^{3}$

$P(X = 2) = 10 * 0.682 * 0.005268 \approx 0.0359$

$P(X = 3) = ^5C_3 * 0.826^3 * (1 - 0.826)^{5-3}$

$P(X = 3) = ^5C_3 * 0.826^3 * (0.174)^2$

$P(X = 3) = 10 * 0.5636 * 0.030276 \approx 0.1706$

$P(X = 4) = ^5C_4 * 0.826^4 * (1 - 0.826)^{5-4}$

$P(X = 4) = 5 * 0.826^4 * (0.174)^1$

$P(X = 4) = 5 * 0.4655 * 0.174 \approx 0.4050$

$P(X = 5) = ^5C_5 * 0.826^5 * (1 - 0.826)^{5-5}\\$

$P(X = 5) = ^5C_5 * 0.826^5 * (0.174)^0$

$P(X = 5) = 1 * 0.3845 * 1 \approx 0.3845$

From the above computations, we have:

$P(X = 0) \approx 0.0002$

$P(X = 1) \approx 0.0038$

$P(X = 2) \approx 0.0359$

$P(X = 3) \approx 0.1706$

$P(X = 4) \approx 0.4050$

$P(X = 5) \approx 0.3845$

See attachment for histogram

<em>From the histogram, we can see that the most likely outcome is at: x = 4</em>

<em>Because it has the longest vertical bar (0.4050 or 40.5%)</em>

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3 years ago

8 centenas x 10<br><br> Help meeeee

djverab [1.8K]

Answer:

80 centimeters

Step-by-step explanation:

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4 years ago

What is this for this question pls help

RideAnS [48]

They are asking you to graph use x1 and y1 x is the one that goes side to side

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3 years ago