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2 years ago

Please help math question !! need range and domain for each picture thank you so much !

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

4 0

Answer: The correct option for figure 1 is (a) and correct option for figure 2 is (b).

Explanation:

Domain is the set of input and range is the set of output.

If a function is defined by f(x), then all the possible values of x is called domain and all the values of f(x) is called range.

In the figure (1) the elements of first set is input(Domain) and the elements of second set is output(Range).

The values of first set are -2,-1,0 and 2, so,

Domain = { -2, -1, 0, 2}

The values of second are -4, -2 and 2, so,

Range = { -4, -2, 2}

In figure (2) the values of x and y are given, the values of x are domain and the values of y are range.

The values of x are -4, -2, 1 and 4, so,

Domain = { -4, -2, 1, 4}

The values of y are -2, 1, 4 and 4,, Since the repetition of elements are not allowed in the set so,

Range = { -2, 1, 4}

Therefore, the option (a) is correct for figure (1) and the option (b) is correct for figure (2).

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Write the inequality for the graph

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Answer:

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Step-by-step explanation:

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3 years ago

Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of

satela [25.4K]

Answer:

The position P is:

$P = 87\^x + 75\^y$ ft Remember that the position is a vector. Observe the attached image

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity $s_0$ is:

$y(t) = y_0 + s_0t -16t ^ 2$

Where $y_0$ is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

$s_0 = 82sin(58\°)$ ft/sec

$s_0 = 69.54$ ft/sec

Thus

$y(t) = 69.54t -16t ^ 2$

The height after 2 sec is:

$y(2) = 69.54 (2) -16 (2) ^ 2$

$y(2) = 75\ ft$

Then the equation that describes the horizontal position of the ball is

$X(t) = X_0 + s_0t$

Where

$X_ 0 = 0$ for this case

$s_0 = 82cos(58\°)$ ft / sec

$s_0 = 43.45$ ft/sec

$X(t) = 43.45t$

After 2 seconds the horizontal distance reached by the ball is:

$X (2) = 43.45(2)\\\\X (2) = 87\ ft$

Finally the vector position P is:

$P = 87\^x + 75\^y$ ft

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3 years ago

Lionel’s work crew packages 150,087 bottles of water every day. If the crew works 5 days, how many bottles can they package in a

yawa3891 [41]

Answer:

im sorry this might not be exactly correct but the answer can be 1,050,609

Step-by-step explanation:

1 week= 7 days so

150,087 × 7 = 1,050,609

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2 years ago

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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2 years ago