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andrezito [222]
3 years ago
7

Solve the sum of two numbers is 23. one number is one less than twice the other. find the two numbers

Mathematics
2 answers:
o-na [289]3 years ago
8 0

x + y = 23

x = 2y-1

y + 2y-1 =23

3y-1 =23

3y =24

y = 24/3 =8

 y = 8

 x = 2*8-1 = 15

15+8 = 23

 the 2 numbers are 8 & 15


morpeh [17]3 years ago
3 0
Let the two numbers be x and y.

Given,

x + y = 23

x = 23 - y

Also given,

y = 2x - 1

y= 2(23 -y) -1

y = 46 - 2y - 1

3y = 45

y = 15

x = 23 - y = 23 - 15 = 8

Hence, the two numbers are 15 and 8.
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Which expression is equivalent to 4/5 divided by 8
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Answer:

40

Step-by-step explanation:

(2x+1/(2x))^5 *(2x -1/(2x))^5

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4 0
2 years ago
Read 2 more answers
A rectangle has the following vertices. Find the area of the rectangle. (9, −1), (−1, 7), (−5, 2), (5, −6)
stiks02 [169]

Answer:  82 sq. units .

Step-by-step explanation:

Let A (9, −1), B (−1, 7), C(−5, 2), D(5, −6) are the vertices of rectangle.

Then we plot them on graph ( as provided in attachment)

Length = AB =\sqrt{(9+1)^2+(-1-7)^2} units  [By distance formula : \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]

=\sqrt{(10)^2+(-8)^2}=\sqrt{100+64}=\sqrt{164}=2\sqrt{41} units

Width = BC = \sqrt{(-1+5)^2+(7-2)^2} units

=\sqrt{4^2+5^2}\\\\=\sqrt{16+25}\\\\=\sqrt{41}

Area = length x width

= 2\sqrt{41}\times\sqrt{41}=2\times41= 82\text{ sq. units}

Hence, the  area of the rectangle is 82 sq. units .

7 0
3 years ago
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