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AlexFokin [52]
3 years ago
12

A map that has a scale of 3 cm: 18 km. If Riverside and Smithville are 54km apart then they are how far apart on the map?

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Setting up the ratio, you get 3/18=x/54. Solve the proportion, you get that Riverside and Smithville are 9 cm apart on the map.


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I am not sure if I did this right can someone explain this to me I am confused . Problem #1
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Yes, you did this right. 5 if the GCF of 15 and 5

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8 0
3 years ago
A cell phone plan costs $200 to start. Then there is a $50 charge each month. Sketch a graph of the cost of the cell phone plan
ch4aika [34]

Answer:

yes

Step-by-step explanation:

yes

4 0
3 years ago
What is the radius and center of the circle given by the equation (x-5)^{2}+(y+2)^{2} = 81/4
artcher [175]

Answer:

The center is (5, -2) and the radius is 9/2

Step-by-step explanation:

The equation of a circle can be written by

(x-h) ^2 + (y-k)^2 = r^2

where (h,k) is the center and r is the radius

(x-5)^{2}+(y+2)^{2} = 81/4

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6 0
3 years ago
The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste and 2460 dollars for 135 kg of waste. (a)
Ulleksa [173]

Answer:

C=18w+30

Step-by-step explanation:

We are given that The monthly charge for a waste collection service is 1830 dollars for 100 kg of waste

So, (x_1,y_1)=(100,1830)

We are also given that The monthly charge for a waste collection service is 2460 dollars for 135 kg of waste.

So, (x_2,y_2)=(135,2460)

We are supposed to find a linear model for the cost, C, of waste collection as a function of the number of kilograms, w.

So, we will use two point slope form :

Formula : y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Substitute the values

y-1830=\frac{2460-1830}{135-100}(x-100)

y-1830=18(x-100)

y-1830=18x-1800

y=18x-1800+1830

y=18x+30

y denotes the cost

x denotes the weight

So, Replace y with C and x with w

C=18w+30

So, a linear model for the cost, C, of waste collection as a function of the number of kilograms, w is C=18w+30

7 0
3 years ago
a rectangular plot of land 8m long and 6m wide.there is a flower bed in the form of a circle of radius 3m.find 1.area of land. 2
mixer [17]

Answer:

1)Area of the Land  is 48 square meters

2) Area of flower bed   is  28.26 square meter

3)Area of land excluding flower bed   is 19.74 square meters

4)cost of planting grass in land  excluding flower bed   is Rs 118.44

Step-by-step explanation:

Given:

Length of the Rectangular plot = 8m

Width of the rectangular plot =  6m

Radius of the circular flower bed = 3m

1)Area of the Land  

Area of the Rectangular plot  = Area of the Land  

Area of the Land   = length x width

Area of the Land   =  8*6

Area of the Land  = 48 square meters-----------------------------(1)

2. Area of flower bed

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Area of flower bed =  area of the circle

Area of flower bed  = \pi r^2

where r is the radius

Now , substituting the values

Area of flower bed = \pi (3)(3)

Area of flower bed = 28.26 square meters-----------------------------(2)

3)Area of land excluding flower bed

Area of land excluding flower bed =  Area of the rectangular land - area of flower beds

Area of land excluding flower bed =  48 - 28.26

Area of land excluding flower bed = 19.74 square meters

4)cost of planting grass in land

Cost of planting grass per square meter = 6

Excluding the flower bed we have  19.74 square meters. to plant grass  for this 19. 74 square meters, the cost will be

=19. 74 \times 6

= Rs 118.44

6 0
3 years ago
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