The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
As you can see, angle 5 and angle 6 are supplementary. And angle 5 and angle 3 are congruent because they are alternate interior angles.
So it will be
x+2 = 180- x+3
move x over from the right to the left
2x+2 = 183
move 2 over from the left to the right
2x = 181
divide by 2
x= 90.5
and angle 3 and angle 1 are vertical angles so they are congruent. Using the angle 3 formula to solve for the answer:
90.5+3 =93.5
When angles are congruent, their measures are congruent, therefore, measure of angle 1 is 93.5
Answer:
4. C
5. 7
6. 3
Step-by-step explanation:
Four:
You have to multiply both of them. Just easy math!
Five:
This one is more complicated. You can see that it is asking you to plug in for a,
F(3):
F(1.25):
So now just subtract the answers. 7-0 equals 7.
Six:
Just look at the graph and see what number corresponds with y(6), or the 6 on the y axis. It appears to be three.
Have a nice day! Hope this helps. Don't forget to mark brainliest!
Y = -2 x - 9
3 x - 4(-2 x - 9 ) = -8
3 x + 8 x + 36 = - 8
11 x = - 44, x = - 4
y = 8 - 9 , y = -1
This is a unique solution, the system is independent.
The two equations graphs intersect and the points where they are touching are belonging to both graphs therefore solutions for both equations.
(2) points (x,y) are
(-1,0) (-1)^2. +0^2=1; 1=1 ✔️
0=-1+1; 0=0✔️
(0, 1). (0)^2. +1^2=1; 1=1 ✔️
1=0+1; 1=1 ✔️
