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Irina-Kira [14]
3 years ago
8

Assume that a procedure yields a binomial distribution with a trial repeated n times. use the binomial probability formula to fi

nd the probability of x successes given the probability p of success on a single trial. round to three decimal places. n = 30, x = 5, p = 1/5
Mathematics
1 answer:
Mamont248 [21]3 years ago
8 0
P(5\ successes)=30C5\times(\frac{1}{5})^{5}\times(\frac{4}{5})^{25}=0.172
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Without diving, how can you tell that the quotient for 5873 ÷ 8 is greater than 700? Is the quotient less than 800?
Ad libitum [116K]
It’s 734.12 so I’m pretty sure it’s less than 800
8 0
2 years ago
Read 2 more answers
The exterior angles of a hexagon are 56º, 730, 2xº, 3x°, 4x° and 5xº.<br> Find the value of x.
Nookie1986 [14]

Answer:

x = 16.5

Step-by-step explanation:

im assuming you meant 73 degrees instead of 730.

56+73 = 129

2x+3x+4x+5x = 14x

360-129 = 231

231 = 14x

231/14 = 16.5

x = 16.5

7 0
3 years ago
Name the rational numbers from the list below -9,0,8,4.19, square root of 7, square root of 4, 4 1/2, -4/5, 1.1616616661
Liula [17]
A rational number can be turned into a fraction

-9...rational number
0..rational number
8..rational number
4.19...rational number
sqrt 7....not rational
sqrt 4...rational
4 1/2...rational
-4/5...rational
1.1616616661 (if this is never ending)....not rational
7 0
3 years ago
4x+8=2x+2 what is x and how to work it out in a way that isn’t complicated
Angelina_Jolie [31]

Answer:

-3

Step-by-step explanation:

4x-2x=2-8

2x=-6

x=-3

3 0
2 years ago
Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and sample size. mu e
Mademuasel [1]

Answer:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".  

Solution to the problem

Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:

X\sim N(\mu =86,\sigma =24)  

We select a sample of size n=64. That represent the sample size.  

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:  

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})  

The mean for the sample distirbution would be given by:

\mu_{\bar x}=86

And the deviation given by:

\sigma_{\bar x} =\frac{24}{\sqrt{64}}=3

And then the distribution for the sample mean is:

\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)

7 0
2 years ago
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