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Stolb23 [73]
2 years ago
5

Palmona Co. establishes a $150 petty cash fund on January 1. On January 8, the fund shows $61 in cash along with receipts for th

e following expenditures: postage, $35; transportation-in, $14; delivery expenses, $16; and miscellaneous expenses, $24. Palmona uses the perpetual system in accounting for merchandise inventory.
Required:
a. Prepare journal entries to establish the fund on January 1.
b. Prepare journal entry to reimburse the petty cash fund on January 8.
c. Prepare journal entries to both reimburse the fund and increase it to $450 on January 8.
Business
1 answer:
saveliy_v [14]2 years ago
6 0

Answer:

Palmona Co Journal entries

1.

Jan-01

Dr Petty cash 150

Cr Cash 150

2.

Jan-08

Dr Postage expense 35

Dr Merchandise inventory 14

Dr Delivery expense 16

Dr Miscellaneous expenses 24

Cr Cash 89

3. Jan-08

Dr Postage expense 35

Dr Merchandise inventory 14

Dr Delivery expense 16

Dr Miscellaneous expenses 24

Cash 89

4.

Jan-08

Dr Petty cash 300

(450-150)

Cr Cash 300

Explanation:

1. To establish petty cash fund

2.To record reimbursement

3.To record reimbursement

4. To record increase in fund balance from 150 to 450

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You have an investment account that started with ​$3 comma 000 10 years ago and which now has grown to ​$6 comma 000. a. What an
zloy xaker [14]

Answer:

The correct answer for option (a) is 7.17% and for option (b) is $48,546.69.

Explanation:

According to the scenario, the given data are as follows:

(a) Present value = $3,000

Future value = $6,000

Time period = 10 years

So, we can calculate the annual rate of return by using following formula:

Rate of return = (( FV ÷ PV)^1/t  -1)

= (( $6,000 ÷ $3,000)^1/10 -1)

= (2)^0.1 - 1

= 1.07177346254 - 1

= .07177 or 7.17%

(b) Present value = $12,000

Rate of interest (r) = 15%

Time period = 10 year

So, we can calculate the Future value by using following formula:

FV = PV × ( 1+r)^t

= $12,000 × ( 1 + 15%)^10

= $12,000 × 4.04555773571

= $48,546.69

8 0
3 years ago
The steam requirements of a manufacturing facility are being met by a boiler whose rated heat input is 5.5 × 106 Btu/h. The comb
e-lub [12.9K]

Solution:

Given Information,

Heat input is ( Q_{in} ) = 5.5 × 10^{6} Btu/h

Combustion efficiency of the boiler (n_{furnance}) = 0.7

Combustion efficiency after turn up (n_{furnance,now}) = 0.8

Operation Hour (t) = 5200h

Unit cost (c) = \frac{23 dollar}{10^{6}Btu }

Calculate heat output from the boiler  Q_{out} = Q_{in} x n_{furnance}

                                                                      = 5.5 x 10^{6} x 0.7

                                                                      = 3.85 x 10^{6} Btu/h

Calculate the heat input to the boiler after the tune-up

(Q_{in} ){new} = Q_{out} / (n_{furnance} ){new}

               = 3.85 x 10^{6} / 0.8

               = 4.8125  x 10^{6} Btu/h

Calculate the saved energy after the tune-up

(Q_{in} ){saved} = Q_{in} - (Q_{in} ){new}

                 = 5.5 x 10^{6} - 4.8125  x 10^{6} Btu/h

                 = 0.6875  x 10^{6} Btu/h

Calculate the annual energy saving ( E_{Saving} )

E_{Saving} = (Q_{in} ){saved} x t

           = ( 0.6875  x 10^{6} Btu/h ) ( 5200 hr/yr)

           = 3575 x 10^{6} Btu/h

Calculate the annual cost saving

Annual cost saving = E_{Annual saving} x Unit cost

                                = 3575 x 10^{6} Btu/h x \frac{23 dollar}{10^{6}Btu }

                                = 82225

4 0
3 years ago
The Morrow Company has assembled the following data pertaining to certain costs that cannot be easily identified as either fixed
Iteru [2.4K]

Answer:

$39,800

Explanation:

From the question above Morrow company has decided to use the measuring cost function method to find its total cost

- $68,400 is the highest cost and $37,600 is the lowest cost

- 6,000 is the highest number of hours and 3,200 is the lowest

The first step is to calculate the cost driver. Let's use the alphabet c to represent the cost driver

(68,400-37,600) / (6,000-3,200)

c = 30,800/2,800

c= $11

Cost driver= $11

The next step is to find the fixed cost. Let's use the alphabet f to represent the fixed cost

68,400= f + ( 11×6000)

68,400= f + 66,000

f= 68,400-66,000

f= $2,400

Fixed cost= $2,400

The final step is to calculate the cost function

Cost function= fixed costs+variable costs×number of units

Fixed cost= $2,400

Variable cost= $11

Number of units= 3,400 hours

= 2,400+(11×3,400)

= 2,400+ 37,400

= $39,800

Hence the total cost at an operating level of 3,400 hours is $39,800

3 0
3 years ago
Why are products made in Third World Countries cheaper than goods made in the US?
Lostsunrise [7]

Answer:

Demand in developing countries is lower and so the price is set lower to match the capacity to pay (such as pharmaceuticals). Locally produced goods, especially the outputs of primary production are generally inexpensive and often will be cheaper in developing countries e.g. bananas.

6 0
3 years ago
Submit Test
Gnoma [55]

Answer:

you didnt put the full question in.

Explanation:

we cant tell what donna bought and cant see the question at all actually

6 0
2 years ago
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