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3 years ago

9

Solve for x 7/6 - (5x-3) = 1/5x - 12

1 answer:

My name is Ann [436]3 years ago

8 0

$\dfrac{7}{6}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{7}{6}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by LCM(6, 5)=30}\\\\30\cdot\dfrac{7}{6}-30\cdot5x+30\cdot3=30\cdot\dfrac{1}{5}x-30\cdot12\\\\5\cdot7-150x+90=6\cdot1x-360\\\\35-150x+90=6x-360\\\\-150x+(35+90)=6x-360\qquad|\text{subtract 6x from both sides}\\\\-156x+125=-360\qquad|\text{subtract 125 from both sides}\\\\-156x=-485\qquad|\text{divide both sides by (-156)}\\\\x=\dfrac{485}{156}$

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4 years ago

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4 years ago

Read 2 more answers

Can anybody help me figure out the area of simple composite figure?

zvonat [6]

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

$A=A_{1} +A_{2}$

where,

$A$ be the area of the given figure

$A_{1}$ be the area of the rectangle

$A_{2}$ be the area of the semicircle.

The area of the rectangle = $lb$ where, l be the length and b be the width
Area of the semicircle = $\frac{1}{2} \pi r^{2}$ , r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

$A_{1} = (16)(12)$ sq ft

or, $A_{1} = 192$ sq ft

$A_{2} = \frac{1}{2} (3.14)(6^{2} )$ sq ft

or, $A_{2}=56.52$ sq ft

So,

$A = 56.52+192$ sq ft

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A=248.5 sq ft.

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7 0

3 years ago

Find the distance between (-6,4) and (-2,1)

zhannawk [14.2K]

Answer:

$d=2.65$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2-(y_2-y_1)^2}$

Simply plug in your 2 coordinates into the formula to find distance <em>d</em>:

$d=\sqrt{(-2-(-6))^2-(1-4)^2}$

$d=\sqrt{(-2+6))^2-(-3)^2}$

$d=\sqrt{(4)^2-9}$

$d=\sqrt{16-9}$

$d=\sqrt{7}$

$d=2.65$

4 0

3 years ago