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hichkok12 [17]
3 years ago
9

Solve for x 7/6 - (5x-3) = 1/5x - 12

Mathematics
1 answer:
My name is Ann [436]3 years ago
8 0

\dfrac{7}{6}-(5x-3)=\dfrac{1}{5}x-12\\\\\dfrac{7}{6}-5x+3=\dfrac{1}{5}x-12\qquad|\text{multiply both sides by LCM(6, 5)=30}\\\\30\cdot\dfrac{7}{6}-30\cdot5x+30\cdot3=30\cdot\dfrac{1}{5}x-30\cdot12\\\\5\cdot7-150x+90=6\cdot1x-360\\\\35-150x+90=6x-360\\\\-150x+(35+90)=6x-360\qquad|\text{subtract 6x from both sides}\\\\-156x+125=-360\qquad|\text{subtract 125 from both sides}\\\\-156x=-485\qquad|\text{divide both sides by (-156)}\\\\x=\dfrac{485}{156}

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Can anybody help me figure out the area of simple composite figure?
zvonat [6]

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

  • A=A_{1} +A_{2}

where,

A be the area of the given figure

A_{1} be the area of the rectangle

A_{2} be the area of the semicircle.

  • The area of the rectangle = lb where, l be the length and b be the width
  • Area of the semicircle = \frac{1}{2} \pi r^{2}, r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

A_{1} = (16)(12) sq ft

or, A_{1} = 192 sq ft

A_{2} = \frac{1}{2} (3.14)(6^{2} ) sq ft

or, A_{2}=56.52 sq ft

So,

A = 56.52+192 sq ft

A = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

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7 0
3 years ago
Find the distance between (-6,4) and (-2,1)
zhannawk [14.2K]

Answer:

d=2.65

Step-by-step explanation:

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Simply plug in your 2 coordinates into the formula to find distance <em>d</em>:

d=\sqrt{(-2-(-6))^2-(1-4)^2}

d=\sqrt{(-2+6))^2-(-3)^2}

d=\sqrt{(4)^2-9}

d=\sqrt{16-9}

d=\sqrt{7}

d=2.65

4 0
3 years ago
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