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Margarita [4]
3 years ago
13

Kong took 15 fewer seconds than Nolan took to complete his multiplication timed test. Kong took 8585 seconds. How many seconds d

id Nolan take?
Mathematics
1 answer:
pashok25 [27]3 years ago
3 0
8585 + 15 = 8600
Nolan took 8600 seconds
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C(x)=4x-2 and d(x)=x^(2)+5, what is (c*d)(x)
lawyer [7]

Answer:4x^3-2x^2+20x-10

Step-by-step explanation:

5 0
3 years ago
Please help me!! i have no clue what i am doing on this one.
Sonja [21]

Answer:

yr answer is G. 21

<h2>stay safe healthy and happy<u>.</u><u>.</u></h2>

8 0
3 years ago
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Which function is the inverse of f Superscript negative 1 Baseline (x) = negative one-fifth x minus four-fifths?
DedPeter [7]

Answer:

f(x) = -5x - 4

Step-by-step explanation:

We want to get the inverse of the following function:

f^-1(x) = (-1/5)x - 4/5

To do that, we have to replace x with f(x) and f^-1(x) with x, as follows:

x = (-1/5)f(x) - 4/5

And then solve for f(x), the inverse of f^-1(x).

x + 4/5 = (-1/5)f(x)

f(x) = -5x + (-5)4/5

f(x) = -5x - 4

To check our result we compute a pair (x, f(x))

x   f(x)

1   -5*1 - 4 = -9

which has to be equivalent to (-9, 1) in the original function

x      f^-1(x)

-9     (-1/5)*(-9) - 4/5 = 1

5 0
3 years ago
Read 2 more answers
Using the exponential growth function for the U. S. population from 1970 through 2003:
jeka94

Answer:

Step-by-step explanation:

Using the exponential growth function for the U. S. population from 1970 through 2003:

A = 205.1e^0.011t

with the U.S. population being 205.1 million in 1970, when would the U. S. population reach 350 million?

A.

2028

B.

2048

C.

2018

D.

2038

We have the expression

A = 205.1e^0.011t

We are asked to find when would the U. S. population reach 350 million

A = 350

350 = 205.1e^0.011t

We divide both sides by 205.1

Divide both sides by 205.1

350/205.1 = 205.1e^0.011t/205.1

1.7064846416 = e^0.011t

We take the log of both sides

log 1.7064846416 = log e^0.011t

log 1.7064846416 = t log 0.011

t = log 1.7064846416/ log 0.011

t = 0.1185057826

7 0
3 years ago
Can someone please explain how to solve this step by step with answer? Thank you.
lidiya [134]

a)

well, she put 4000, and she earned in interest 960, so her accumulated amount is just their sum, 4960.

b)

now, it doesn't say, so we're assuming is <u>simple interest</u>, as opposed to compound interest.


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill&960\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to r\%\to \frac{r}{100}\dotfill\\ t=years\dotfill &3 \end{cases} \\\\\\ 960=(4000)(r)(3)\implies \cfrac{960}{(4000)(3)}=r\implies 0.08=r \\\\\\ \stackrel{\textit{converting to percentage}}{r=0.08\cdot 100}\implies r=\stackrel{\%}{8}


c)

let's make the rate 1% greater then, and check


\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\dotfill\\ P=\textit{original amount deposited}\dotfill & \$4000\\ r=rate\to \stackrel{8+1}{9\%}\to \frac{9}{100}\dotfill&0.09\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(4000)(0.09)(3)\implies I=1080 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{at 9\%}}{1080}-\stackrel{\textit{at 8\%}}{960}\implies \stackrel{\textit{that much more}}{120}

4 0
3 years ago
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