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3 years ago

What is the circumference of a circle with a radius of 56 inches

Mathematics

1 answer:

DIA [1.3K]3 years ago

3 0

Answer:

351.8584

Step-by-step explanation:

circumfrence is pi times diameter, diameter is twice the amound of radius.

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Find the solutions for a triangle with a = 16, c =12, and B = 63º.

maks197457 [2]

Answer:

b. A = 71.6°; C = 45.40°; b =15.0

Step-by-step explanation:

The missing values can be found with the help of the Law of Cosine and properties of triangles:

Side b (Law of Cosine)

$b = \sqrt{a^{2}+c^{2}-2\cdot a \cdot c \cdot \cos B}$

$b = \sqrt{16^{2}+12^{2}-2\cdot (16)\cdot (12) \cdot \cos 63^{\circ}}$

$b \approx 15.022$

Angle A (Law of Cosine)

$\cos A = -\frac{a^{2} - b^{2}-c^{2}}{2\cdot b \cdot c}$

$\cos A = - \frac{16^{2}-15.022^{2}-12^{2}}{2\cdot (15.022)\cdot (12)}$

$\cos A = 0.315$

$A= \cos^{-1} 0.315$

$A \approx 71.639^{\circ}$

Angle C (Sum of internal angles in triangles)

$C = 180^{\circ} - 63^{\circ} - 71.639^{\circ}$

$C = 45.361^{\circ}$

Hence, the right answer is B.

6 0

3 years ago

A DVD player is regularly priced at $79.95 and is on sale for 30% off. What is the amount of the discount?

monitta

Answer:

266.5

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

A rectangle has a width of 3 units. The rectangle's length is 5 times its width.

Korolek [52]

Answer:

width=3

then length=5×3

now,

Area=l×b

= 15×3

=45

8 0

3 years ago

Read 2 more answers

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two

Vikentia [17]

Answer:

the probability of no defects in 10 feet of steel = 0.1353

Step-by-step explanation:

GIven that:

A roll of steel is manufactured on a processing line. The anticipated number of defects in a 10-foot segment of this roll is two.

Let consider β to be the average value for defecting

So;

β = 2

Assuming Y to be the random variable which signifies the anticipated number of defects in a 10-foot segment of this roll.

Thus, y follows a poisson distribution as number of defect is infinite with the average value of β = 2

i.e

$Y \sim P( \beta = 2)$

the probability mass function can be represented as follows:

$\mathtt{P(y) = \dfrac{e^{- \beta} \ \beta^ \ y}{y!}}$

where;

y = 0,1,2,3 ...

Hence, the probability of no defects in 10 feet of steel

y = 0

$\mathtt{P(y =0) = \dfrac{e^{- 2} \ 2^ \ 0}{0!}}$

$\mathtt{P(y =0) = \dfrac{0.1353 \times 1}{1}}$

P(y =0) = 0.1353

4 0

3 years ago

A corporate team-building event costs $19plus an additional $1 per attendee. How many attendees can there be, at most, if the bu

Mars2501 [29]

Answer:

There can be at most $12$ attendees in a corporate team-building event.

Step-by-step explanation:

Let $x$ denotes number of attendees in a corporate team-building event.

Fixed cost = $19

Cost charged per attendee = $1

Budget for the corporate team-building event = $31

Therefore,

$19+1(x)\leq 31\\19+x\leq 31\\x\leq 31-19\\x\leq 12$

So, there can be at most $12$ attendees in a corporate team-building event.

8 0

3 years ago