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vodomira [7]
1 year ago
15

The length of a rectangle is three more than twice the width. Determine the dimensions that give a total area of 27ft squareda.

create an equation in terms of w to model this situationb. what are the solutions to this equation c. What are the length and width of the rectangle
Mathematics
1 answer:
Nuetrik [128]1 year ago
5 0

ok

Area = 27ft^2

length = l

width = w

Equation

l = 2w + 3

Section A

Area

A = l*w

A = (2w + 3)* w or A = 2w^2 + 3w

27 = 2w^2 + 3w

2w^2 + 3w - 27 = 0 This is the equation

Section B

2w^2 - 6w + 9w - 27 = 0

2w(w - 3) + 9(w - 3) = 0

(w - 3)(2w + 9) = 0

w1 - 3 = 0 2w + 9 = 0

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<span>7N - 2N + 3P + 2P

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Put them together to get :
5N+5P

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3 years ago
(9 1/3 + 4 2/3) +7 - (-12)= <br><br> A: 2 and 5/8<br> B: -13 and 13/16<br> C: 14<br> D: 4
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4 years ago
Muiltiply 8x^2(x^2+2xy-6y^2) simplify your answer
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The answer would be 8x^4 + 16x^3y - 48x^2y^2

In order to find this, multiply 8x^2 by each term individually.

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Now you can put them all in a row.

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The sum of two numbers is 52. The greater number is 4 more than the smaller number. Which equation can be used to solve for the
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Answer:

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Step-by-step explanation:

Let's name the smaller number x.

The greater number would then be (x+4).

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<u>The equation we could then set up would be:</u>

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<em>Now we can solve the equation to find the two numbers if needed.</em>

<u>Here is how:</u>

x+x+4=52

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