The length of a rectangle is three more than twice the width. Determine the dimensions that give a total area of 27ft squareda.
create an equation in terms of w to model this situationb. what are the solutions to this equation c. What are the length and width of the rectangle
1 answer:
ok
Area = 27ft^2
length = l
width = w
Equation
l = 2w + 3
Section A
Area
A = l*w
A = (2w + 3)* w or A = 2w^2 + 3w
27 = 2w^2 + 3w
2w^2 + 3w - 27 = 0 This is the equation
Section B
2w^2 - 6w + 9w - 27 = 0
2w(w - 3) + 9(w - 3) = 0
(w - 3)(2w + 9) = 0
w1 - 3 = 0 2w + 9 = 0
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22+26+28+30+39+44+62+63= 314
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Answer:
Hi there!
Your answer is:
-1 >=x>5
This can be broken down to:
x <= -1
x>5
Which fits your requirements!
Answer: y = -3
<u>Step-by-step explanation:</u>
-8x - 5y = -1
<u>+8x </u> <u>+8x </u>
-5y = 8x - 1
<u> ÷-5 </u> <u> ÷-5</u> <u>÷-5</u>
y =
y(2) =
=
=
= -3
Factor out the GCF, which is 4.... 4(4a+3b)
Answer:
x
=
−
5.35424868 ,
−
10.64575131
Step-by-step explanation: