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vodomira [7]
10 months ago
15

The length of a rectangle is three more than twice the width. Determine the dimensions that give a total area of 27ft squareda.

create an equation in terms of w to model this situationb. what are the solutions to this equation c. What are the length and width of the rectangle
Mathematics
1 answer:
Nuetrik [128]10 months ago
5 0

ok

Area = 27ft^2

length = l

width = w

Equation

l = 2w + 3

Section A

Area

A = l*w

A = (2w + 3)* w or A = 2w^2 + 3w

27 = 2w^2 + 3w

2w^2 + 3w - 27 = 0 This is the equation

Section B

2w^2 - 6w + 9w - 27 = 0

2w(w - 3) + 9(w - 3) = 0

(w - 3)(2w + 9) = 0

w1 - 3 = 0 2w + 9 = 0

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Question 18
Svetlanka [38]

Answer:

Step-by-step explanation:

J and K are equal

8x - 23 = 6x + 11            Add 23 to both sides

8x = 6x + 11 + 23           Combine the right

8x = 6x + 34                  Subtract 6x from both sides

8x - 6x = 34                   Combine the left

2x = 34                           Divide by 2

x = 34/2

x = 17

=================================

M and L are both supplementary to J and K respectively.

J = 8x - 23

J = 8*17 - 23

J = 136-23

J = 113

K = 113

===================================

M + 113 = 180

M = 180 - 113

M = 67

L = 67

5 0
2 years ago
Suppose AC = 48, find the value of x. Then, find the length of AB and the length of BC.<br> 1
gladu [14]

Answer:

2x-4+3x+2=48

5x-2=48

5x=48+2

5x=50

x=10

Step-by-step explanation:

this

6 0
3 years ago
Please help me real quick ​
Eddi Din [679]

Answer:

x= 7

Step-by-step explanation:

11x-2 = 75

11(7) - 2

77 - 2 = 75

x= 7

3 0
3 years ago
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