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vodomira [7]
1 year ago
15

The length of a rectangle is three more than twice the width. Determine the dimensions that give a total area of 27ft squareda.

create an equation in terms of w to model this situationb. what are the solutions to this equation c. What are the length and width of the rectangle
Mathematics
1 answer:
Nuetrik [128]1 year ago
5 0

ok

Area = 27ft^2

length = l

width = w

Equation

l = 2w + 3

Section A

Area

A = l*w

A = (2w + 3)* w or A = 2w^2 + 3w

27 = 2w^2 + 3w

2w^2 + 3w - 27 = 0 This is the equation

Section B

2w^2 - 6w + 9w - 27 = 0

2w(w - 3) + 9(w - 3) = 0

(w - 3)(2w + 9) = 0

w1 - 3 = 0 2w + 9 = 0

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Step-by-step explanation:

Hey there!

Follow the steps to get answer.

  • Use one point formula and find 1st equation.
  • After that you find the slope of second equation.
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  • Put slope value of equation in equation (i) and simplify them to get equation.

The equation of a line passing through point (2,3) is;

(y-3)= m1(x-2).......(i).

Another equation is;

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2nd equation..

Now, From equation (ii)

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Comparing equation (ii) with y = mx+c.

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Slope = -1/2.

For perpendicular lines,

m1 \times m2 =  - 1

m1 \times  \frac{ - 1}{2}  =  - 1

Therefore the slope is 2.

Put value of slope (m1) in equation (i). We get;

(y - 3) = 2(x - 2)

Simplify them to get equation.

(y - 3) = 2x - 4

y = 2x - 1

Therefore the required equation is y = 2x-1.

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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Step-by-step explanation:

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