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Sliva [168]
3 years ago
8

PLEASE HELP ASAP 25pts

Mathematics
2 answers:
Damm [24]3 years ago
5 0
Yup it's B

9*4 - 2(8) = 20
5(11-8) = 15

So

20 > 15
MrRissso [65]3 years ago
4 0
The answer is B my friend

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A figure is broken into a rectangle and a triangle. The triangle has a base of 2 and two-thirds feet and height of 3 feet. The r
ohaa [14]

Answer:

b=2\frac23\:\sf ft

Area of triangle = 4 ft²

Area of rectangle = 6\frac23\: \sf ft^2

Area of irregular figure = 10\frac23\: \sf ft^2

Step-by-step explanation:

\begin{aligned}\sf Base\:of\:triangle\:(b) & = 5-2\frac13\\\\& = \dfrac{15}{3}-\dfrac73\\\\ & = \dfrac83\\\\ & = 2\frac23\:\sf ft \end{aligned}

\begin{aligned}\sf Area\:of\:a\:triangle & =\dfrac12 \sf \times base \times height\\\\& = \dfrac12 \times b \times 3\\\\ & = \dfrac12 \times \dfrac83 \times \dfrac31\\\\ & = \dfrac{24}{6}\\\\ & = 4\: \sf ft^2\end{aligned}

\begin{aligned}\sf Area\:of\:rectangle& =\sf length \times width\\\\& = 5 \times 1\frac13\\\\ & = \dfrac51\times \dfrac43\\\\& = \dfrac{20}{3}\\\\ & = 6\frac23\: \sf ft^2\end{aligned}

\begin{aligned} \sf Area\:of\:irregular\:figure & = \sf area\:of\:triangle+area\:of\:rectangle\\\\ & = 4 + 6\frac23\\\\ & = 10\frac23\: \sf ft^2\end{aligned}

5 0
2 years ago
Read 2 more answers
Given: Quadrilateral PAST, TX = AX; TP || AS<br> Prove: Quadrilateral PAST is a parallelogram.
poizon [28]

1) Quadrilateral PAST, TX=AX, \overline{TP} \parallel\overline{AS} (given)

2) \angle XPT \cong \angle XSA and \angle XTP \cong \angle XAS (alternate interior angles theorem)

3) \triangle TXP \cong \triangle AXS (AAS)

4) \overline{TP} \cong \overline{AS} (CPCTC)

5) PAST is a parallelogram (a quadrilateral with two pairs of opposite congruent sides is a parallelogram)

8 0
2 years ago
Determine whether each ordered pair is a solution to the inequality x+y&lt;−1.
polet [3.4K]

Answer:

Choice A.  (10, -1)
Choice B.  (-8, 9)
Choice D.  (6, -3)

Step-by-step explanation:

If we plug the coordinates of point A into the inequality, then we get,
x+y > -2

10 + (-1) > -2
9 > -2
That last inequality is a true statement since 9 is to the right of -2 on the number line. That means (10,-1) is a solution. Choice A is one of the answers.
Choices B and D are also answers
for similar reasons.
Something like choice C is not a solution because
x+y > -2
-1+(-9) > -2
-10 > -2
Which is false.
You should find that choice E is false as well.

If you graphed the inequality and all of the points mentioned (see below), then you can visually confirm the answers. Notice how points A, B and D are in the blue shaded region which is the solution set.
The point E on the boundary does not count as a solution. This is due to the lack of "or equal to" portion of the inequality sign. That visually shows point E is not a solution. Point C isn't a solution either as it's nowhere near the blue shaded region.

3 0
2 years ago
12x a y b ÷ (-6x a y) quotient.
Nady [450]
If that is what it looks like it is, 12 divided by -6 is -2, the a's cancel out, the y's cancel out, and you're left with -2b.  I'm not sure what else this could be.
7 0
3 years ago
If the 7 was moved one place to the left, its value would be
Fudgin [204]

Answer:

173,080

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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