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3 years ago

11 + (19+6)= (11+____) + 6

Mathematics

2 answers:

ad-work [718]3 years ago

8 0

11+(19+6)= (11+19)+6 so it's the associative property

pshichka [43]3 years ago

6 0

19.
Due to the associative property of addition, you may switch the parentheses, keeping everything still equal.<span />

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If the average of 3 numbers and 8 is 25 what is the sum of the three numbers

Gennadij [26K]

Let sum of 3 numbers be x.

Average of 3 numbers and 8 = $\frac{x + 8}{4}$

25 = $\frac{x +8}{4}$

100 = x +8

x= 92.

The sum of 3 numbers is 92.

3 0

3 years ago

Law of radicals

andrey2020 [161]

Answer:

1) $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

Step-by-step explanation:

1) $\sqrt{x^7}$

We know that $\sqrt{x}=x^{\frac{1}{2}$

So, $\sqrt{x^7}=x^{\frac{7}{2}$

2) $\sqrt[3]{y^5}$

We know that $\sqrt[3]{x}=x^{\frac{1}{3}$

So, $\sqrt[3]{y^5}=y^{\frac{5}{3}$

3) $\sqrt[5]{a^{12}}$

We know that $\sqrt[5]{x}=x^{\frac{1}{5}$

So, $\sqrt[5]{a^{12}}=a^{\frac{12}{5} }$

4) $\sqrt[4]{z^{9}}$

We know that $\sqrt[4]{x}=x^{\frac{1}{4}$

So, $\sqrt[4]{z^{9}}=z^\frac{9}{4}$

6 0

3 years ago

A theater has 20 seats per row each row is filled before the next row is used on Wednesday eight people are seated in the last r

tiny-mole [99]

Answer:

448

Step-by-step explanation:

3 0

3 years ago

For the figure shown, find m 1.<br> 115 degrees<br> 56 degrees<br> m 1=°

atroni [7]

I believe it would be 115 plus 56. subtract that from 180. i believe thisbis your answer

3 0

3 years ago

Are the equations lxl – 3 = 7 and [x] = 10 equivalent?

zvonat [6]

They're not equivalent.

$|x|$ (vertical bars) represents the absolute value of x. How it works is that it turns negative numbers positive but leaves 0 and positive numbers alone (hence it gets a number's distance from 0 on the number line).

$[x]$ (square brackets) usually represents the floor function, which returns the largest integer that is less than or equal to x. (The floor of x can also be written as $\lfloor x \rfloor$ --- it depends on what your textbook/source says).

To solve $|x| - 3 = 7$ , you first transform it into the equivalent equation $|x| = 10$ . Then by definition of absolute value, there are only two solutions for the first equation: x = 10 or x = -10.

[x] = 10 has infinitely many solutions. For example, the floor of 10 is 10, so $[10] = 10$ , thus a solution for the second equation is x = 10

The floor of 10.1 is 10, so $[10.1] = 10$ , thus another solution for the second equation is x = 10.1.

The two equations do not have the same solution set (as x = 10.1 does not solve |x| - 3 = 7 but solves [x] = 10), so they're not equivalent.

5 0

3 years ago