1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetlanka [38]
3 years ago
8

11 + (19+6)= (11+____) + 6

Mathematics
2 answers:
ad-work [718]3 years ago
8 0
11+(19+6)= (11+19)+6 so it's the associative property
pshichka [43]3 years ago
6 0
19.
Due to the associative property of addition, you may switch the parentheses, keeping everything still equal.<span />
You might be interested in
What is the slope if you have (1,1) and (-3,-2)?
Serga [27]

Given two points (X1,Y1) and (X2,Y2) on a line, the slope =(Y2 - Y1) /(X2 - X1).

You are given the points (1,3) and (3,-2). Implying X1 =1 , Y1 =3, X2=3, Y2=-2

Use the formula for the slope above to answer the question. If you still have problems getting the correct answer, ask for more help.

Your answer should be a negative fraction or decimal if you are using a calculator.

3 0
2 years ago
Read 2 more answers
-2 (4t-3)+6t=5t-2 solve
ElenaW [278]
-8t+6+6t=5t-2
-2t+6=5t-2
-2t-5t=-2-6
-7t=-8
-7 -7
T=1.14 or 1 1/7
8 0
3 years ago
What is the width of a rectangle with a length of 18 cm and an area of 72 cm²
Pachacha [2.7K]

area = L x W

area = 72

L=18

72= 18 x w

w=72/18 = 4

width is 4 cm


 

5 0
3 years ago
Read 2 more answers
A) 9<br> B) 0 <br> C) Undefined<br> D) 6
Usimov [2.4K]
9 is the answer probably

5 0
3 years ago
"Find y". I got this wrong and want to understand why and how to do the problem. Can someone please help?
podryga [215]

Answer:

y=\frac{15\sqrt{3} }{4}

Step-by-step explanation:

Well what you have here are two right triangles within another right triangles created by an altitude. This results in 3 similar triangles (see attached for reference)

As a result , using the properties of similar triangles, and taking ratios of their sides of the medium triangle and the largest triangle, we can form the following relationship:

\frac{b}{z}=\frac{y}{x} = \frac{z}{a+b}  (we know that a+b = 15), hence the equation becomes:

\frac{b}{z}=\frac{y}{x} = \frac{z}{15}  ----------eq 1

If we consider the largest triangle, we will see that

cos 30° = z / 15

but from our special angles (see second attachment) we know that cos 30° = (√3)/2

hence

(√3)/2 = z / 15

z = (15√3) / 2 --------eq 2

from the same largest triangle, we will also see that

sin 30° = x / 15

similarly from our special angles, we know that sin 30° = 1/2

hence,

1/2 = x/15

x = 15/2 --------eq 3

now that we have values for x and z, we can neglect the first term of equation 1 and form an equality with x, y and z

\frac{y}{x} = \frac{z}{15}

y = x\frac{z}{15}  (substituting the values for x and z that we found above)

y = (15/2) · [ (15√3) / 2] / 15

y = (15√3) / 4

y=\frac{15\sqrt{3} }{4}

8 0
3 years ago
Other questions:
  • Li deposited $17,500 into a bank account that earned simple interest each year. After 2 years, he had earned $2975 in interest.
    11·1 answer
  • Can an angle ever have the same measure as its complement? Explain.
    15·1 answer
  • Which is the graph of the inequality: y&lt; (1/2x -2)^3
    9·1 answer
  • It is 10 3/5 miles from Alston to Barton and 12 1/2 miles from Barton to Chester. The distance from Alston to Durbin, via Barton
    8·2 answers
  • Evaluate the variable expression when a=-4, b=2, c=-3, and d =4. b-3a/bc^2-d​
    15·1 answer
  • A rectangle has an area of 0.24 of a square meter.
    6·1 answer
  • True or false, the centroid of a triangle is also the center of gravity of the triangle. ​
    12·1 answer
  • Make <br> x<br> the subject of the formula<br> x<br> −<br> 3<br> =<br> q
    9·1 answer
  • Compare the graph of g(x) = 6x2 with the graph of f(x) = x2.
    14·1 answer
  • Given: f = {(0, 1), (2, 4), (4, 6), (6, 8)} and g = {(2, 5), (4, 7), (5, 8), (6, 9), (7, 5)}
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!