Question

HELP PLZ

Answer 1

Answer:

$x=\frac{-7-\sqrt{17}}{2}\textrm{ or }x=\frac{-7+\sqrt{17}}{2}$

Step-by-step explanation:

Given:

The equation is given as:

$x^2=-7x-8$

Rearrange the above equation in standard quadratic equation of the form $ax^2+bx+c=0$

Adding $7x + 8$ on both sides, we get

$x^2+7x+8=0$

Here, $a=1,b=7,c=8$

Now, we solve this using quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\x=\frac{-7\pm \sqrt{7^2-4(1)(8)}}{2(1)}\\x=\frac{-7\pm \sqrt{49-32}}{2}\\x=\frac{-7\pm \sqrt{17}}{2}\\\\\\\therefore x=\frac{-7-\sqrt{17}}{2}\textrm{ or }x=\frac{-7+\sqrt{17}}{2}$

Answer 2

Answer:  option D.

Step-by-step explanation:got a 100 on it