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dangina [55]
3 years ago
15

4)

Mathematics
2 answers:
Ksivusya [100]3 years ago
6 0

Answer: option B is correct

Step-by-step explanation:

If five pounds of fudge = $17.00

One pound will equal 17.00/5 = $3.40

If one pound of fudge equals $3.40, at the same rate, twelve pounds will cost:

$3.40 × 12= $40.80

Leto [7]3 years ago
3 0

Answer:

C

Step-by-step explanation:

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Malika bought 7 new pairs of shoes. Each pair of shoes cost the same amount and was discounted by $21.75.
ikadub [295]

Multiply the amount of the discount by pairs of shoes:

21.75 x 7 = 152.25

Add that to the total she spent:

152.25 + 654.50 = 806.75

Divide the total by pairs of shoes:

806.75/7 = $115.25

The answer is C. $115.25

3 0
3 years ago
Help, please!!!<br><br> Simplify. (4/9)^2=
alina1380 [7]

Answer:

Exact form: \frac{16}{81}

Decimal form: 0.1975308

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2 years ago
The Gallup Poll uses a procedure called random digit dialing, which creates phone numbers based on a list of all area codes in A
kondaur [170]
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5 0
3 years ago
Read 2 more answers
What is the mistake NEED ANSWER ASAP​
julsineya [31]

Answer:

The answers are in the image.

Step-by-step explanation:

Charlie made the mistake by not getting the equation equal to zero.

x^2 - 9x + 8 = 16

Subtract 16 to both sides making it equal to 0.

x^2 - 9x - 8 = 0

Using Quadratic Formula to Solve for x.

4 0
2 years ago
Geometry area question. Please help!
timurjin [86]
You can calculate polygon area with only apothem OR side length.

apothem only
area = apothem^2 * 6 * tan (180/6)
area = 10.4^2 * 6 * 0.57735
area = 108.16 * <span> <span> <span> 3.4641 </span> </span> </span>
area = <span> <span> <span> 374.677056 </span> </span> </span> square yards

side length only
area = 6 * 12^2 * / 4*tan(30)
area = 864 / 4 * 0.57735
area = 864 / <span> <span> <span> 2.3094 </span> </span> </span>
area = <span> <span> <span> 374.1231488698 </span> </span> </span> square yards

If apothem and side length were given with more precision, the answers would be closer.

Source:
http://www.1728.org/polygon.htm


5 0
3 years ago
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