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SIZIF [17.4K]
3 years ago
10

Find the volume of the prism. write your answer as a decimal.​

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

161.21

Step-by-step explanation:

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A composite solid consists of a cube with edges of length 6cm and a square pyramid with base edges of length 6cm and height of 6
icang [17]

Answer: The volume of the solid is 324 cm³

Step-by-step explanation:

Formula for determining the volume if a cube is s³

Where s represents the length of each side of the cube.

From the information given, s = 6 cm

Volume = 6³ = 216 cm³

The formula for determining the volume of the square base pyramid is expressed as

Volume = Area × height × 1/3

From the information given,

Length of square base = 6 cm

Height = 6 cm

Area of square base = 6² = 36 cm²

Volume of square base pyramid

= 36 × 6 × 1/3 = 108 cm³

The volume of the solid would be the sum of the volume of the cube and the volume of the square base pyramid. It becomes

216 + 108 = 324 cm³

5 0
4 years ago
Brandy solved 1/6÷5 by using a related multiplication expression. What multiplication expression did she use?
tekilochka [14]

Answer:

THE ANSWER IS 30

Step-by-step explanation:

We can solve this problem by multiplication expressions. See below.

1/6 ÷5  = \frac{1}{6}  * \frac{1}{5}  = \frac{1}{30}  = 30

8 0
3 years ago
Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
Read 2 more answers
Cos 200. Cos 115- Sin 200. Sin 115=
Harrizon [31]
Cos 200= -0.939692621. cos 115-sin200=-0.080598118 Sin 115=0.906307787
6 0
4 years ago
Which of the functions graphed below has a removable discontinuity?<br> A<br> B<br> C<br> D
PtichkaEL [24]
<h2>Answer with explanation:</h2>

We know that a removable discontinuity occurs when:

The left and the right hand limit of the function exist at a point and are equal but is unequal to the function's value at that point.

Also it is a  point on the graph such that it is undefined at that point.

The graph that has a removable discontinuity is attached to the answer.

Since, at x=0 the left hand and the right hand limit of the function exist but the function is not defined at x=0 , since in the graph there is a open circle at x=0 that means that the point is removed from the range.

5 0
3 years ago
Read 2 more answers
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