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3 years ago

How do you solve polynomial equation by factoring 2x^3 - 12x^2 = 32x - 192

1 answer:

7 0

$2x^3 - 12x^2 = 32x - 192\\
2x^3-12x^2-32x+192=0\\
2(x^3-6x^2-16x+96)=0\\
2(x^2(x-6)-16(x-6))=0\\
2(x^2-16)(x-6)=0\\
2(x-4)(x+4)(x-6)=0\\
x=4 \vee x=-4 \vee x=6$

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HELPP please.. please pleaae

Zinaida [17]

Answer:

A=80

B=31

C=64

Step-by-step explanation:

A, 69, and b will equal 180 since it forms a straight line

A+69+b=180

to solve for A we subtract 53+47 from 180 and get 80

80+69+b=180

to get B we subtract 80+69 from 180 and get 31

to get c we add 85+b and subtract it from 180 getting c=64

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3 years ago

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Help me ASAP please and I hate math

xxMikexx [17]

The answer is y is greater y > -8

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3 years ago

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Ben’s garden supply store sells a gardening kit that normally costs $95. This week it is on sale for 35% off. How much does it c

gizmo_the_mogwai [7]

The gardening kit costs $33.25. Multiply $95 by 0.35.

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2 years ago

Solve the following inequality.

Anika [276]

Solving the inequality given algebraically, the solution of the inequality for the value of m is:

m < -4 OR m > 3

Given the following inequality,

$\frac{m - 2}{3} < -2 \\$

4m + 3 > 15

Let's solve algebraically for the value of m in both inequality statements given.

$\frac{m - 2}{3} < -2 \\$

Multiply both sides by 3

$\frac{m - 2}{3} \times 3 < -2 \times 3\\\\m - 2 < -6$

Add 2 to both sides

$m - 2 + 2 < -6 + 2\\\\m < -4$

4m + 3 > 15

Subtract 3 from each side

4m + 3 - 3 > 15 - 3

4m > 12

Divide both sides by 4

$\frac{4m}{4} > \frac{12}{4} \\\\$

m > 3

Therefore, solving the inequality given algebraically, the solution of the inequality for the value of m is:

m < -4 OR m > 3

Learn more here:

brainly.com/question/24434501

8 0

3 years ago

What are the solution(s) of x2-4-0?

Elanso [62]

Answer:

For $x^2 - 4 = 0$ , x = 2, or x = - 2.

Step-by-step explanation:

Here, the given expression is :

$x^2 - 4 = 0$

Now, using the ALGEBRAIC IDENTITY:

$a^2 - b^2 = (a-b)(a+b)$

Comparing this with the above expression, we get

$x^2 - 4 = 0 = x^2 - (2)^2 = 0\\\implies (x-2)(x+2) = 0$

⇒Either (x-2) = 0 , or ( x + 2) = 0

So, if ( x- 2) = 0 ⇒ x = 2

and if ( x + 2) = 0 ⇒ x = -2

Hence, for $x^2 - 4 = 0$ , x = 2, or x = - 2.

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3 years ago

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