Answer:
5.6 days
Step-by-step explanation:
We are given;
Initial Mass; N_o = 25 g
Mass at time(t); N_t = 25/2 = 12.5 (I divide by 2 because we are dealing with half life)
k = 0.1229
Formula is given as;
N_t = N_o•e^(-kt)
Plugging in the relevant values;
12.5 = 25 × e^(-0.1229t)
e^(-0.1229t) = 12.5/25
e^(-0.1229t) = 0.5
(-0.1229t) = In 0.5
-0.1229t = -0.6931
t = -0.6931/-0.1229
t = 5.6 days
1) function f(x)
x - 5
f(x) = ----------------
3x^2 - 17x - 28
2) factor the denominator:
3x^2 - 17x - 28 = (3x + 4)(x - 7)
x - 5
=> f(x) = -----------------------
(3x + 4) (x - 7)
3) Find the limits when x → - 4/3 and when x → 7
Lim of f(x) when x → - 4/3 = +/- ∞
=> vertical assymptote x = - 4/3
Lim of f(x) when x → 7 = +/- ∞
=> vertical assymptote x = 7
Answer: there are assympotes at x = 7 and x = - 4/3
Answer:C
Step-by-step explanation: 7+5=12 12x9.25=111.00
