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Elza [17]
3 years ago
13

Given real numbers a,b > 1.

Mathematics
1 answer:
irina [24]3 years ago
8 0

Answer:

FALSE

Step-by-step explanation:

Recall that a function f(x) is of exponential order c, if there exists a constant M such that and a real r such that

|f(x)|\leq Me^{cx}\;(x\geq r)

Now, take a = 2.5 and b = 2

The functions

f(x)=(2.5)^x\;g(x)=2^x

are both exponential of order 1, since  

\lim_{x \to \infty}\frac{f(x)}{e^x}=\lim_{x \to \infty}\frac{g(x)}{e^x}=0

but a>b

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Answer:

45

Step-by-step explanation:

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What is the density in grams per milliliter of a substance with a mass of 50 grams and a volume of 100 ml
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4 years ago
compare the right-hand and left-hand derivatives to show that the function is not differentiable at the point P. find all points
Softa [21]
f(x)=  \left \{ {{ \sqrt{x} } \atop {2x-1}} \right. 
\\
\\ f'(x)=  \left \{ {{  \frac{1}{2\sqrt{x}} } \atop {2}} \right. 
\\
\\  f'(1)=  \left \{ {{  \frac{1}{2}} \atop {2}} \right. 
\\
\\ f'(1^-) \neq f'(1^+)

Therefore, the function is not differentiable at x = 1.

f(x)= \sqrt{x} 
\\
\\f'(x)= \frac{1}{2 \sqrt{x} } 
\\
\\f'(0)=\frac{1}{2 \sqrt{0} } = \infty

Therefore, the function is not differentiable at x = 0.
3 0
3 years ago
A rocket is launched from a tower. The height of the rocket, why in feet is related to the time after launch, X and seconds, by
Maru [420]

Given:

Consider the height of the rocket, in feet after x seconds of launch is

y=-16x^2+152x+74

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The time at which the rocket will reach its max, to the nearest 100th of a second.

Solution:

We have,

y=-16x^2+152x+74

It is a quadratic polynomial with negative leading coefficient. So, it is a downward parabola.

Vertex of a downward parabola is the point of maxima.

To find the time at which the rocket will reach its max, we need to find the x-coordinate of the vertex.

If a quadratic function is f(x)=ax^2+bx+c, then the vertex is

Vertex=\left(-\dfrac{b}{2a},f\left(-\dfrac{b}{2a}\right)\right)

Here, a=-16,b=152,c=74.

So,

-\dfrac{b}{2a}=-\dfrac{152}{2(-16)}

-\dfrac{b}{2a}=-\dfrac{152}{-32}

-\dfrac{b}{2a}=4.75

So, x-coordinate of the vertex is 4.75.

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3 years ago
Put the following equation of a line into slope intercept form simplify all fractions: 2Y minus X equals -8
kozerog [31]
2y-x=8
2y=8+x
———————
y=4+1/2x
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3 years ago
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