Answer:
your answer is -5,-10
Step-by-step explanation:
please mark brainliest
Answer:
1.5 unit^2
Step-by-step explanation:
Solution:-
- A graphing utility was used to plot the following equations:

- The plot is given in the document attached.
- We are to determine the area bounded by the above function f ( x ) subjected boundary equations ( y = 0 , x = -1 , x = - 2 ).
- We will utilize the double integral formulations to determine the area bounded by f ( x ) and boundary equations.
We will first perform integration in the y-direction ( dy ) which has a lower bounded of ( a = y = 0 ) and an upper bound of the function ( b = f ( x ) ) itself. Next we will proceed by integrating with respect to ( dx ) with lower limit defined by the boundary equation ( c = x = -2 ) and upper bound ( d = x = - 1 ).
The double integration formulation can be written as:

Answer: 1.5 unit^2 is the amount of area bounded by the given curve f ( x ) and the boundary equations.
Answer:
it has to equal -1 x= to -1 parenthesees
1 times -1= -1 its true for that 1 answer but not the others
Notice that
(1 - <em>x</em>)⁵ (1 + 1/<em>x</em>)⁵ = ((1 - <em>x</em>) (1 + 1/<em>x</em>))⁵ = (1 - <em>x</em> + 1/<em>x</em> - 1)⁵ = (1/<em>x</em> - <em>x</em>)⁵
Recall the binomial theorem:

Let <em>a</em> = 1/<em>x</em>, <em>b</em> = -<em>x</em>, and <em>n</em> = 5. Then

We get an <em>x</em> ³ term for
2<em>k</em> - 5 = 3 ==> 2<em>k</em> = 8 ==> <em>k</em> = 4
so that the coefficient would be
