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3 years ago

What is the value of x?

Mathematics

2 answers:

sasho [114]3 years ago

6 0

Answer:

$\boxed{\sf x = 80}$

Step-by-step explanation:

A quadrilateral inscribed in a circle has opposite sides equal to 180.

So,

x + x + 20 = 180

2x + 20 = 180

Subtracting 20 from both sides

2x = 180 - 20

2x = 160

Dividing both sides by 2

x = 80

kherson [118]3 years ago

5 0

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▹ Answer

x = 80

▹ Step-by-Step Explanation

x + x + 20 = 180

2x + 20 = 180

2x = 180 - 20

2x = 160

x = 80

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

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Jack can text 180 words in 2 minutes and 45 seconds. What is his unit rate in texts per second?

grigory [225]

Answer: 1.091 which is approximately 1 word per second

Step-by-step explanation:

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3 years ago

A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee

katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

$^nC_r=\dfrac{n!}{(n-r)!r!}$

Given : Total multiple-choice questions = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

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= $^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84$

No. of ways to answer 4 open-ended problems

= $^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15$

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

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Hence, the correct answer is option A) 1260

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4 years ago

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BartSMP [9]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

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evablogger [386]

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