Answer:
a). Radius r of the small sector= 12cm
b). Perimeter of the shape= 68 cm
c). Angle= 47.7°
Step-by-step explanation:
a). Radius of the big sector= 24 cm
Arc if the big sector= 20 cm
Arc of the small sector= 10 cm
For the radius r of the small sector
r/10 = 24/20
r=(10*24)/20
r= 24/2
r= 12 cm
Radius r of the small sector= 12cm
b). Perimeter of the shape
= Total length of the shape
Let's note that the other side of the sector is also the radius= 24 cm
Perimeter= 20+24+24
Perimeter of the shape= 68 cm
c) the angle
Length of arc = 2πr*(angle/360)
Let angle = b
Length of arc = 20cm
20= 2*3.14*24*(b/360)
(20*360)/(2*3.14*24)= b
47.7°= b
Angle= 47.7°
Answer:
1/2
Step-by-step explanation:
The slope is given by
m = (y2-y1)/(x2-x1)
= (6 - -1)/(12 - -2)
= (6+1)/(12+2)
7/14
1/2
The key idea of the transformation called a rotation is the moving of the plane a certain angle around a fixed point.
Answer:
125/12
Step-by-step explanation:
1st problem-no
2nd problem-yes
3rd problem-yes
4th problem-no
Answer:
3 weeks
Step-by-step explanation:
Two puppies from the same litter are named Bruno Puppy Weight and Jasper. Their weights during the first weeks are plotted on the coordinate grid. At which age did Bruno and Jasper weigh the same?
Solution:
We can see that Bruno and Jasper weight is represented by a straight line. Let y represent the weight of the puppies in ounce and x represent the age in weeks.
For Bruno:
The line passes through (1, 10) and (5, 16), hence the equation of the line is:

For Jasper:
The line passes through (0, 12) and (3, 13), hence the equation of the line is:

To find the age at which both puppies weighed the same, we have to solve equation 1 and 2 simultaneously. Subtract equation 1 from 2:
-1.167x + 3.5 = 0
1.167x = 3.5
x = 3
Put x = 3 in equation (2)
y = (1/3)(3) + 12 = 13
The solution is (3, 13)
Therefore both Jasper and Bruno weigh the same weight of 13 ounce at 3 weeks of age