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natka813 [3]
4 years ago
8

A circular post in a cafeteria has a diameter of 3 feet. Which of these is

Mathematics
1 answer:
timurjin [86]4 years ago
6 0

Answer:

9.42 feet

Step-by-step explanation:

The circumference is π × diameter.

3.14 × 3 = 9.42

The circumference of the circular post is 9.42 feet.

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What is the common ratio for the sequence 5,-10,20,-40?
algol [13]

Answer:

The COMMON RATIO of the sequence is -2.

Step-by-step explanation:

Here, the given sequence  is:

5, -10, 20 ,-40

Here, The first term ( a 1 ) of the sequence is (5)

The second term (a 2) of the sequence is (-10)

Third term of sequence (a 3) is 20

Now, calculating the common ratio (r) of sequence ,we get:

\frac{a_2}{a_1} =  r  = (\frac{-10}{5}) = -2\\\frac{a_3}{a_2} =r  = (\frac{20}{-10}) = -2

So, here r =(-2)

⇒ The COMMON RATIO of the sequence is -2.

Hence, the given sequence in in GEOMETRIC PROGRESSION.

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3 years ago
How do I solve a given parallelogram
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3 years ago
X=5 y=7 find the constant of variation
larisa86 [58]
When two variable quantities have a constant ratio, their relationship is called a direct variation. It is said that one variable varies directly as the other.
3 0
3 years ago
Write the linear inequality shown in the graph. The gray area represents the shaded region.
Katarina [22]

Answer:

D

Step-by-step explanation:

find the slope (-3,1), and see the shaded region for if it's over or under the line

7 0
4 years ago
Read 2 more answers
A circular cylindrical container, open at the top, and having a capacity of 24pi cubic inches, is to be manufactured. If the cos
otez555 [7]

Answer: radius r = 2 inches

height h = 6 inches

Step-by-step explanation:

Given;

Volume V = 24πin3

Volume of a cylinder is given by

V = πr^2h

h = V/πr^2. ....1

Where, h = height and r = radius of cylinder

For the surface area of the cylinder with open top. we have,

S = 2πrh + πr^2

For the cost of materials used, let k represent the cost of materials used for the body of the cylinder.

Then, for the bottom will be 3k

Total cost will be represented by C, which gives

C = 2πrhk + 3πr^2k. .....2

Substituting eqn 1 to 2, we have;

C = 2πrVk/πr^2 + 3πr^2k

C = 2Vk/r + 3πr^2k

The material cost is minimum at dC/dr = 0

dC/dr = -2Vk/r^2 + 6πrk =0

6πrk = 2Vk/r^2

r^3 = 2V/6π

r = (2×24π/6π)^-3

r = (8)^-3

r = 2

Substituting r = 2 into eqn1

h = 24π/π(2^2)

h = 24/4 = 6

h = 6

5 0
4 years ago
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