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3 years ago

Answer nineteen and twenty thanksss

Mathematics

1 answer:

Nataliya [291]3 years ago

6 0

19. Supplementary
20. Complementary

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If 45 cookies will serve 15 students,how many cookies are needed for 30 students?

blondinia [14]

Simply multiply 45 by 2 and you get your answer which is 90 cookies

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3 years ago

Solve: log (7t + 2) = 2<br>t =

IrinaK [193]

Answer:

t = 14

Step-by-step explanation:

log (7t + 2) = 2

Raise each side to the power of 10

10 ^log (7t + 2) =10^ 2

7t+2 = 100

Subtract 2 from each side

7t+2-2 = 100-2

7t = 98

Divide each side by 7

7t/7 = 98/7

t = 14

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3 years ago

Read 2 more answers

104, 137, 154, 131, x; mean = 130

pochemuha

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3 years ago

A tank with a capacity of 100 gallons initially contains 50 gallons of water with 10 pounds of salt in solution. fresh water ent

steposvetlana [31]

Let $A(t)$ be the amount of salt (in pounds) in the tank at time $t$ . We're given that $A(0)=10\text{ lb}$ .

The rate at which the amount of salt in the tank changes is given by the ODE

$A'(t)=\dfrac{2\text{ gal}}{1\text{ min}}\cdot\dfrac{0\text{ lb}}{1\text{ gal}}-\dfrac{1\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{50+(2-1)t\text{ gal}}$

$A'(t)+\dfrac{A(t)}{50+t}=0$

$(50+t)A'(t)+A(t)=0$

$\bigg((50+t)A(t)\bigg)'=0$

$(50+t)A(t)=C$

$A(t)=\dfrac C{50+t}$

Given that $A(0)=10$ , we find that

$10=\dfrac C{50+0}\implies C=500$

so that the amount of salt in the tank is described by

$A(t)=\dfrac{500}{50+t}$

The tank will be filled when $50+t=100$ , or after $t=50$ minutes. At this time, the amount of salt in the tank is

$A(50)=\dfrac{500}{50+50}=5\text{ lb}$

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3 years ago

Can someone solve this, you don’t have to type an explanation, thank you.

levacccp [35]

<h2>Answer:</h2>

The answer is D 62°

<h2>Step-by-step explanation:</h2>

Equation:

4x-2=62

Solving for x:

4x-2+2=62+2

4x=64

4x/4=64/4

x=16

Plug 16 into the equation to see if the answer is correct:

4•16-2=62

4•16=64

64-2=62°

<em>Hope this helped!</em>

3 0

2 years ago