All categories

3 years ago

15 crackers weigh 69 grams. how many kilograms is this?

Mathematics

1 answer:

Marrrta [24]3 years ago

6 0

Answer:

$0.069\ kg$

Step-by-step explanation:

we know that

1 kg=1,000 g

using proportion

Find out how many kilograms are 69 grams

Let

x -----> the weight in kg

$\frac{1}{1,000}\frac{kg}{g} =\frac{x}{69}\frac{kg}{g}\\\\x=\frac{69}{1,000}\\\\x=0.069\ kg$

You might be interested in

The area of ABED is 49 square units. Given AGequals9 units and ACequals10 units, what fraction of the area of ACIG is represent

stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

$A=b^{2}$

where b is the length side of the square

we have

$A=49\ units^2$

substitute

$49=b^{2}$

$b=7\ units$

therefore

$AB=BE=ED=AD=7\ units$

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

$A=(AC)(AG)$

substitute the given values

$A=(9)(10)=90\ units^2$

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

$A=(DE)(DG)$

we have

$DE=7\ units$

$DG=AG-AD=9-7=2\ units$

substitute

$A=(7)(2)=14\ units^2$

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

$A=(EF)(CF)$

we have

$EF=AC-AB=10-7=3\ units$

$CF=BE=7\ units$

substitute

$A=(3)(7)=21\ units^2$

step 5

sum the shaded areas

$14+21=35\ units^2$

step 6

Divide the area of of the shaded region by the area of ACIG

$\frac{35}{90}$

Simplify

Divide by 5 both numerator and denominator

$\frac{7}{18}$

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0

2 years ago

Find the area of the composite figure.

MArishka [77]

2 × 6 = 12

12 ÷ 2 = 6

2 × 14 = 28

10 × 20 = 200

6 + 28 + 200 = 234

7 0

2 years ago

A hotel charges $90 per day for a double room $80 per day for a single room. If a total of 80 single and double rooms are occupi

SashulF [63]

Answer:

the number of single room is 27 and the number of double room is 53

Step-by-step explanation:

Let x is the number of single room

Let y is the number of double room

We know that:

x + y = 80 <=> x = 80 -y (1)

80x +90y= 6930 (2)

Substitute (1) in (2) we have:

80 (80 - y) + 90y = 6930

<=> 6400 - 80y +90y = 6930

<=> y = 53

> x = 80 - 53 = 27

the number of single room is 27 and the number of double room is 53

4 0

2 years ago

If angle 3 is congruent to angle 4, then find the measure of angle 3 to the ratio of the measure of angle 4.

djyliett [7]

Answer:

bhdwkvdveqvhjvhjawvhjcddvscg

wvvdgvewagvdgwvgdvwgevdegw

Step-by-step explanation:

8 0

3 years ago

How much father is Earth from the Sun than it is from Venus?

daser333 [38]

Earth to the sun is 92.96 million miles away from each other. The sun to Venus is 67.24 million miles. I hope I helped!

4 0

3 years ago

Read 2 more answers