They are called transformations.
512, the formula for volume is length x width x height :)
Solution:
As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.
We consider a line , one dimensional if it's thickness is negligible.
So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.
So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.
Answer:
<h3>5</h3>
Step-by-step explanation:
Given the expression
2a^3−10ab^2+3a^3−ab^2−7
We are to find the coefficient of a^3
First is to collect the like terms;
2a^3−10ab^2+3a^3−ab^2−7
= 2a^3+3a^3−10ab^2−ab^2−7
= 5a^3-11ab^2-7
From the resulting equation, you can see that the coefficient of the term having a^3 is 5
Answer:
discrete i think i might be wrong
Step-by-step explanation: