Q1 Express in the form 1.0<br> 4:12

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that give

mestny [16]

Answer:

a. answer to a can be found in the attached file

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

Step-by-step explanation:

"A seed randomly blows around a complex habitat. It may land on any of three different soil types: a high-quality soil that gives a 0.8 chance of seed survival, a medium-quality soil that gives a 0.3 chance of survival, and a low-quality soil that gives only a 0.1 chance of survival. These three soil types (high, medium, and low) are present in the habitat in proportions of 30:20:50, respectively. The probability that a seed lands on a particular soil type is proportional to the frequency of that type in the habitat. a. Draw a probability tree to determine the probabilities of survival under all possible circumstances. b. What is the probability of survival of the seed, assuming that it lands"c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

a. Find the probability tree as attached below

b. Pr[survival] = Pr[good&survive]+Pr[medium&survive]+Pr[low&survive]=

0.24+0.06+0.05 = 0.35

c. Assume that the seed has a 0.2 chance of dying before it lands in a habitat. What is its overall probability of survival?

Pr[survival] = Pr[survival|lands] * Pr[lands] = 0.35 * 0.2 = 0.07

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7 0

3 years ago

Plzzzzz help tomorrow is my maths test

maria [59]

16 ) GO...

a) 5487 × ( 65 + 35 ) = 5487 × 100 = 548700

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b) 647 × ( 112 - 12 ) = 647 × 100 = 64700

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c) 502 × 1,008 = ( 500 + 2 ) ( 1,000 + 8 ) = 500,000 + 4,000 + 2,000 + 16 = 506,016

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17 ) Go...

a) 585 × 16 × 625 = 585 × 4 × 4 × 25 × 25 = 585 × 4 × 25 × 4 × 25 = 585 × 100 × 100 = 5,850,000

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b) 147 × 50 × 2 = 147 × 100 = 14,700

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18) Go...

look : 1729 = ( 1400 + 329 ) = 7 × 200 + 7 × 47 = 7 ( 200 + 47 ) = 7 × 247 = 7 × 13 × 19

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19) Go...

look : 96 = 16 × 6 = 2⁴ × 2 × 3 = 2⁵ × 3

Thus ;

the factors are : ( 1 , 2 , 3 , 4 , 6 , 8 , 12 , 16 , 24 , 32 , 48 , 96 )

3 0

2 years ago

A study of 35 golfers showed that their average score on a particular course was 92. The sample standard deviation was 5. We wan

svlad2 [7]

Answer:

$t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$

Step-by-step explanation:

We have a sample of size n = 35, $\bar{x} = 92$ and $s = 5$ . As we want to construct a 95% confidence interval to estimate the value of the true population mean $\mu$ , we should use the pivotal quantity given by $T = \frac{\bar{X}-\mu}{S/\sqrt{n}}$ which comes from the t distribution with n - 1 = 35 - 1 = 34 degrees of freedom. Besides we should use the t-value $t_{\alpha/2} = t_{0.05/2} = t_{0.025} = 2.0322$ , i.e., regarding the t-distribution with 34 degrees of freedom, we have an area of 0.025 above 2.0322 and below the probability density function. The rationale behind this is that $P(-2.0322\leq T\leq 2.0322) = 0.95$ because of the simmetry of the t distribution.