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Airida [17]
3 years ago
15

Select the equation equivalent to the line 3x - 2y = 14.

Mathematics
1 answer:
vovangra [49]3 years ago
3 0
Without answer choices, there are infinitely many solutions.  It can be any multiple of the reference equation or it could be the equation written is point-slope form or slope-intercept form....
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X+5 divided by 3 is less than or equal to 2
hichkok12 [17]
\frac{x+5}{3}  \leq 2
times both sides by 3
x+5≤6
minus 5 both sides
x≤1
5 0
3 years ago
Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
professor190 [17]

Answer:

Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

1. That 1R1, 2R2, 3R3, 4R4 to the relation be reflexive and,

2. Observe that

  • 1R4 and 4R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 4R1 and 1R2, then 4 must be related with 2.

Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

  • since 1R2, then 2 must be related with 1.
  • since 1R4, 4 must be related with 1.

and the analysis for be transitive is the same that we did in a).

Observe that

  • 1R2 and 2R1, then 1 must be related with itself.
  • 4R1 and 1R4, then 4 must be related with itself.
  • 2R1 and 1R4, then 2 must be related with 4.
  • 4R1 and 1R2, then 4 must be related with 2.
  • 2R4 and 4R2, then 2 must be related with itself

Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

c) We need a new relation reflexive, symmetric and transitive containing R1.

For be reflexive

  • 1 must be related with 1,
  • 2 must be related with 2,
  • 3 must be related with 3,
  • 4 must be related with 4

For be symmetric

  • since 1R2, 2 must be related with 1,
  • since 1R4, 4 must be related with 1.

For be transitive

  • Since 4R1 and 1R2, 4 must be related with 2,
  • since 2R1 and 1R4, 2 must be related with 4.

Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

5 0
3 years ago
Angle A and B are supplementary angles. The measure of angle B is twice the measure of angle A minus 24. Find the measure of the
ivann1987 [24]

Answer:

A = 58

B = 112

Step-by-step explanation:

A + B = 180                           Supplementary angles

B = 2A - 24                           Given

Substitute for B in the first equation

A + 2A - 24  = 180

3A - 24 = 180                         Add 24 to both sides

3A = 180 + 24                        Combine the right

3A = 204                               Divide both sides by 3

A = 204/3

A = 68

B = 2A - 24

B = 2*68 - 24

B = 136 - 24

B = 112

5 0
3 years ago
I GIVE BRAINLILSTTTT
soldi70 [24.7K]

Answer:The most specific answer is H if you need explanation tell me

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
5x - 2y = 3
svlad2 [7]

Answer: Your answer is c

Step-by-step explanation:  The first thing you can do is add the two equations together to cancel out x

5x-2y=3

-5x+4y=9

added them together will get us 2y=12, from here divide 2 and get y=6

Plug 6 into the first equation and solve for x.

5x-2(6)=3

5x-12=3, add 13 to the other side

5x=15, divide 5 and get the answer

x=3

5 0
3 years ago
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