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vazorg [7]
3 years ago
6

Solving systems of equations using substitution

Mathematics
1 answer:
Maurinko [17]3 years ago
5 0
Equation 1)  y = 3 - x
Equation 2)  8x + y = -4

Rearrange equation 1 so that x and y are on the same side. To do so, you add x to both sides.

1)  x + y = 3
2)  8x + y = -4

Subtract equations from each other.

-7x = 7

Divide both sides by -7.

x = 1

Plug in 1 for x in the first equation.

y = 3 - x

y = 3 - 1

Simplify.

y = 2

(1, 2)   ==> x = 1, y = 2

~Hope I helped!~


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b

Step-by-step explanation:

3 0
1 year ago
1) f(x) = 2x + 4, g(x) = 4x2 + 1; Find (g ∘ f)(0).
Sholpan [36]

Answer:

<h2>(g \: \circ \: f)(0) = 17</h2>

Step-by-step explanation:

f(x) = 2x + 4

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<h3>(g \: \circ \: f)(x) = 4( ({2x + 4})^{2} ) + 1 \\  = 4(4 {x}^{2}  + 16x + 16) + 1 \\  =  {16x}^{2}  + 64x + 16 + 1</h3>

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Now to find (g ∘ f)(0) substitute the value of x that's 0 into (g ∘ f)(0)

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<h3>(g \: \circ \: f)(0) = 16( {0})^{2}  + 64(0) + 17 \\</h3>

We have the final answer as

<h3>(g \: \circ \: f)(0) = 17</h3>

Hope this helps you

8 0
4 years ago
Graph the linear equation. <br> 3x-4y=12 Thanks
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Hi 
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